Answer:
The mass of 
in the container is 2.074 gram
Explanation:
Given:
Volume of 
lit
Equilibrium constant 
The reaction in which is produced
⇄ 
Here equal moles of and 
is formed.
From the formula of equilibrium constant,
M
Above value shows,
So in 2 L no. moles of = 
moles.
So mass of 0.122 mole of is = 
g
Therefore, the mass of in the container is 2.074 gram
The mole ratio would be 2:2:2
Answer : The correct option is, (C) 0.675 M
Explanation :
Using neutralization law,
where,
= concentration of 
= 13.5 M
= concentration of diluted solution = ?
= volume of = 25.0 ml = 0.0250 L
conversion used : (1 L = 1000 mL)
= volume of diluted solution = 0.500 L
Now put all the given values in the above law, we get the concentration of the diluted solution.
Therefore, the concentration of the diluted solution is 0.675 M
Nitrogen (around 78%), Oxygen (around 21%), and Argon (around 1%).
Hope this helps :)
Tin metal reacts with hydrogen fluoride to produce tin(II) fluoride and hydrogen gas according to the following balanced equation.
Sn(s)+2HF(g)→SnF2(s)+H2(g)
Sn(s)+2HF(g)→
SnF
2
(s)+
H
2
(g)
How many moles of hydrogen fluoride are required to react completely with 75.0 g of tin?
Step 1: List the known quantities and plan the problem.
Known
given: 75.0 g Sn
molar mass of Sn = 118.69 g/mol
1 mol Sn = 2 mol HF (mole ratio)
Unknown
mol HF
Use the molar mass of Sn to convert the grams of Sn to moles. Then use the mole ratio to convert from mol Sn to mol HF. This will be done in a single two-step calculation.
g Sn → mol Sn → mol HF
Step 2: Solve.
75.0 g Sn×1 mol Sn118.69 g Sn×2 mol HF1 mol Sn=1.26 mol HF
75.0 g Sn×
1
mol Sn
118.69
g Sn
×
2
mol HF
1
mol Sn
=1.26 mol HF
Step 3: Think about your result.
The mass of tin is less than one mole, but the 1:2 ratio means that more than one mole of HF is required for the reaction. The answer has three significant figures because the given mass has three significant figures.
