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DaniilM [7]
3 years ago
13

What is the value of x in the solution to the following system of equations?

Mathematics
1 answer:
Tanya [424]3 years ago
5 0
x. =2 and y= 0 is the values of given linear equation
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Which statement BEST describes why the exponential function exceeds the linear function?​
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Which of the figures below have the same area?
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100 POINTS!! OMG YOU NEED TO SOLVE THIS!
natita [175]

Answer:

The correct answer is: \Delta BDE \cong \Delta BFK by <em>rule</em> ASA rule of congruence.

Step-by-step explanation:

First let us prove \Delta BDE \cong \Delta BFK by rule ASA (rule of congruence).

<u>Congruent side:</u>

\overline{BD} \cong \overline{BF} (Given)

<u>Congruent angles:</u>

1. By definition of perpendicular,

\angle{BFK} = 90 \textdegree \ (Since \ \overline{FK} \ is \ perpendicular \ to \ \overline{AB} \ (\overline{FK} \perp \overline{AB} =Given))

Also,

\angle{BDE} = 90 \textdegree \ (Given)

Therefore,

\angle{BDE} \cong \angle{BFK}

or you can say,

\angle{D} \cong \angle{F}

2. Common angle between \Delta BDE \ and \ \Delta BFK is \angle{B}

In a nutshell, in \Delta BDE,

\angle{B} (Angle)

\overline{BD} (Side)

\angle{BDE} (Angle)

are congruent to the following angle, side and angle of \Delta BFK:

\angle{B} (Angle)

\overline{BF} (Side)

\angle{BFK} (Angle)

Therefore, by ASA rule of congruence, we can say \Delta BDE \cong \Delta BFK.

<em>Since both triangles are congruent</em>, the sides \overline{ED} and \overline{FK} are also congruent.

5 0
3 years ago
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