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DaniilM [7]
3 years ago
13

What is the value of x in the solution to the following system of equations?

Mathematics
1 answer:
Tanya [424]3 years ago
5 0
x. =2 and y= 0 is the values of given linear equation
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PleAse help ASAP!!!!!!
Brums [2.3K]

Answer:

D

Step-by-step explanation:

D is the best Answer.

6 0
2 years ago
4. The Television Chocolate Room was painter
VashaNatasha [74]

Answer:

C

Step-by-step explanation:

5 0
2 years ago
I NEED THIS ANSWER ASAP
telo118 [61]

Answer:

3 quarts and 3 cups

Step-by-step explanation:

4 cups=1 quart

Capacity: 5x4+2=22 cups

Right now 1x4+3=7

22-7=15 cups

12/4 +3

3 quarts and 3 cups more

6 0
2 years ago
A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0
2 years ago
Two partners are starting a wedding planning business. The total investment is $45,000. Their investments are in the ratio 4:5.
JulijaS [17]

Answer:

Hey there!

Think of 45000 being split to 9 pieces.

Each piece would be 5000 dollars.

Thus, the ratio would be 20000 to 25000

Hope this helps :)

7 0
3 years ago
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