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mina [271]
3 years ago
12

All 204g of sugar will dissolve in 100g of water at 25ºC. This is the solubility of sugar. If 55g of sugar is dissolved in 50g o

f water at 25ºC then the solution is _______ compared to a solution that has 5g of sugar dissolved in 50g of water at 25ºC.
a. saturated
b. supersaturated
c. diluted
d. concentrated
Chemistry
2 answers:
Kay [80]3 years ago
6 0
Ha, that's funny, I've been trying to find that answer too,---- let me guess, you're in Connections Academy?
zysi [14]3 years ago
5 0

<u>Answer:</u> The correct answer is Option d.

<u>Explanation:</u>

Saturated solutions are defined as the solutions in which no more solute particles can be dissolved in the solvent.

Supersaturated solutions are defined as the solution in which more amount of solute particles is present than the solvent particles.

Diluted solution is defined as the solution in which only a little solute is dissolved in a certain amount of solvent.

Concentrated solution is defined as a solution which contains a large amount of solute relative to solution that has lesser amount of solute.

We are given:

204 g of sugar is dissolved in 100 g of solvent. So, solubility of sugar will be \frac{204}{100}=2.04 at 25ºC

For solution 1: 55g of sugar is dissolved in 50g of water at 25ºC. The solubility will be \frac{55}{50}=1.1 at 25ºC

For solution 2: 5g of sugar dissolved in 50g of water at 25ºC.  The solubility will be \frac{5}{50}=0.1 at 25ºC

So, the solution having solubility equal to 1.1 is concentrated as compared to the solution having solubility equal to 0.1

Hence, the correct answer is Option d.

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Answer:

December.

Explanation:

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From the list below, choose which groups are part of the periodic table
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The periodic table of the elements are describe the electronic configuration of the elements on which the properties of the elements depends. Among the given groups only metal, non-metal and semi-metal group are the part of periodic table. The metallic property depends upon the binding energy of the electrons with the nucleus. Thus the elements which have the valence electrons more near to the nucleus that is s-block elements are more metallic in nature. On the other hand the elements which have the valence electrons far from the nucleus are more non-metallic in nature like p-block elements. However the binding energy or the attraction of the outermost electrons to the nucleus depends not only its valence electrons position but also some other factors like shielding effect, effective nuclear charge etc.

The elements which are in between the metals and non-metals can be classified as semi-metals.

Although the conductivity of a material is an inherent property of the metals but sometime the nonmetals or semi-metals are also behave like a conductor due to presence of the other elements, thus it cannot be a p[property of the periodic table. Similarly acidity, flammable gases are not part of the periodic table.      

3 0
3 years ago
Calculate the concentrations of all species present in a 0.26 M solution of ethylammonium chloride (C2H5NH3Cl).
Alina [70]

Answer:

0.00000223

Explanation:

pKa for C2H5NH3+ = 10.7

pKw = 14.0

pKa + pKb = pKw

10.7 + pKb = 14.0

pKb = 14.0 - 10.7

pKb = 3.30

C2H5NH3Cl is a salt of ethylamine and HCl so it will dissolve in water to produce  C2H5NH3^+ + Cl^-

The base hydrolysis reaction:  C2H5NH3^+(aq) + H2O(l) <=> C2H5NH2(aq) + H3O^+(aq)

This reaction is described by Kb.

Kb = [C2H5NH2][H3O^+]/[C2H5NH3^+]

Let [C2H5NH2] = [H3O^+] = x,

so [C2H5NH3^+] = 0.26 - x

Kb = x^2/(0.26 - x) = 2.00 x 10^-11  

Let's solve for x. In this equation,  It is possible to solve without the use quadratic equation. So we can assume that 0.26 - x  is approximately equal to 0.26.  We won't know until we do the calculation.

We get:  x^2 + 2.00 x 10^-11x - 4.99 x 10^-12 = 0

With the use of a quadratic calculator.

x = 2.23 x 10^-6 M = [C2H5NH2] = [H3O^+]

0.26 - x  is just 0.26 M in this problem because 2.23 x 10^-6 M is insignificant.

[C2H5NH3^+] = 0.26 M = [Cl^-]

NOTE:

pH = -log [H3O^+] = -log(2.23 x 10^-6) = 5.65

Ka is the acid dissociation constant

Kb is the base dissociation constant

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