1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
trapecia [35]
3 years ago
13

You need to purify 2.0 grams of an impure sample of Acetanilide. The sample is contaminated with aniline. After the purification

is complete you isolate 0.8 grams of acetanilide and record a melting point range of 108-110 °C. Complete the following calculations and show your work.
a. Calculate the minimum amount of distilled water you would use to complete the recrystallization.
b. How much acetanilide will still be dissolved in solution even after the sample is cooled to 0 °C?
c. Calculate the % recovery and the % error for the melting point.
d. Why is the percent recovery less than 100%? Describe multiple sources for loss of sample.

Chemistry
1 answer:
marusya05 [52]3 years ago
3 0

Answer:

Following are the answer to this question:

Explanation:

In the given question an attachment file is missing, that is attached. please find the attached file, and the following are the description of the given points:

a. At 100 degrees in 100 mL 5 g is dissolved.  

For, it required:

\to 2g = 100 \times \frac{2}{5}

         = 40 \ \ ml \ of \ water.  

b. At 0 degrees 100 mL dissolve in 0.3 g.  

So, the dissolve:

\to 40 \ ml= 0.3\times \frac{40}{100}

               = 0.12g.

After refrigeration 0.12 g will still be dissolved.  

c. After dissolving and freezing, precipitation can occur which would still be impure if the cooling is instantaneous. The added solvent was also too hard to recrystallize. The solvent was placed below its place of reservation.  

d. Recovery percentage:

\to \frac{0.8}{2}\times100

\to 40 \ \%

The melting point of acetanilide:

\to 114.3^{\circ}.

Found=109(medium)  

Melting point error percentages:

= \frac{114.3-109}{114.3}\\\\=4.63 \ \%

You might be interested in
Vapor obtained by evaporating 0.495 grams of an unknown liquid is collected in a 127 mL flask. At 371 K, the pressure of the vap
lidiya [134]

Answer:

The molar mass in g/mol is 121.4 g/m

Explanation:

Let's apply the Ideal Gases Law to solve this:

P . V = n . R. T

V = 125 mL → 0.125L

P = 754 Torr

760 Torr ___ 1 atm

754 Torr ____ (754 / 760) = 0.992 atm

Moles = Mass / Molar mass

0.992 atm . 0.125L = (0.495 g / MM) . 0.082 . 371K

(0.992 atm . 0.125L) / (0.082 . 371K) = (0.495 g / MM)

4.07x10⁻³ mol = 0.495 g / MM

MM = 0.495 g / 4.07x10⁻³ mol → 121.4 g/m

3 0
3 years ago
Calculate the mass percent of H in C3H8O3.<br> %
ki77a [65]

Answer:

because of it being that you have inferno dragon plsss

6 0
3 years ago
Briefly discuss interpretations of your observations and results. Discuss how your observations illustrated LeChatelier's princi
Dvinal [7]

Answer:

Le Chatelier's principle can be applied in explaining the results

Explanation:

According to Le Chatelier's principle, when a constraint such as a change in concentration in this case is imposed on a chemical system in equilibrium, the system will adjust itself in such a way as to annul the constraint imposed.

Hence, when the color of the solution was more like that of the control, the reaction would shift towards the left. Similarly, when the color was more like it was towards the reactant, the reaction would shift towards the right.

If we were to prepare calcium oxalate, we should prepare it in a base solution. This is because when the base was added to calcium oxalate, it did not form any precipitate but when an acid was added to the calcium oxalate, it formed a precipitate.

4 0
2 years ago
Ce cantitate de O se gaseste in 5,8 g hidroxid de magneziu
coldgirl [10]

Answer:

separare pâlnii de picurare balon cotat. 1. 2. 3. 4 5 6 7. 8. 9. 1 ... Mod de lucru: 25 g Na2SO4∙7H2O se dizolvă în cantitatea minim ... Exemple: NaOH – hidroxid de sodiu.

Explanation:

make me as brain liest

4 0
3 years ago
The absorbance of an equilibrium mixture containing FeSCN2 was measured at 447 nm and found to be 0.347. What is the equilibrium
Ksenya-84 [330]

Answer:

The concentration is C = 1.11 mol/L

Explanation:

From the question we are told that

     The absorbance is  A = 0.347

       The length is  l =  447 nm  =  447 *10^{-7} \ cm

     

Generally absorbance is mathematically represented as

        A =  \epsilon*  C * l

where \epsilon is the molar absorptivity of  FeSCN2  with a value \epsilon  =  7.0*10^3 L/cm/mol

 and  C is the equilibrium concentration of FeSCN2

So  

       C = \frac{A}{\epsilon *  l  }

substituting values

        C = \frac{0.347}{7.0*10^{3} *  447 *10^{-7}  }

         C = 1.11 mol/L

5 0
2 years ago
Other questions:
  • As more bulbs are connected in series in a circuit, what happens to the brightness with which each glows?
    9·2 answers
  • Calculate the percent error in calculating the pH of a 0.040 M HCl solution that is also 0.010 M in HNO3 using ionic strength an
    15·1 answer
  • To stop an object that is in motion on a frictionless surface, you stop applying a force.
    5·1 answer
  • Reasons why convection is responsible for the uneven heating of the air in the atmosphere
    6·1 answer
  • PLEASE HELP ME ASAP Identify the arrows that show the correct direction of heat transfer.
    7·1 answer
  • 675 g of carbon tetrabromide is equivalent to how many
    11·2 answers
  • Daniel is testing objects for his science experiment. He has a chart listing the mystery objects' densities, but no other inform
    7·2 answers
  • True or false? Recycling metal reduces fuel costs as less metal ore needs to be mined and transported.
    5·1 answer
  • Please help and thank you so much
    5·1 answer
  • Which molecule can't be exist?<br>A)NCl3 B)OF6 C)ONF3 D)PCl3<br>​
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!