Answer:
9.8 × 10^21
Explanation:
Equation of the reaction;
Cd(s) + Ni^2+(aq) ----> Cd^2+(aq) + Ni(s)
E°cell= E°cathode - E°anode
E°cathode= -0.25 V
E°anode = -0.40 V
E°cell= -0.25 - (-0.40)
E°cell = 0.65 V
∆G= -nFE°cell
∆G= -(2 × 96500 × 0.65)
∆G = -125450 J
From;
∆G= -RTlnK
lnK = ∆G/-RT
K= e^∆G/-RT
K= e^-[-(125450/8.314 × 298)]
K= 9.78 × 10^21
To calculate an electron configuration, divide the periodic table into sections to represent the atomic orbitals, the regions where electrons are contained. Groups one and two are the s-block, three through 12 represent the d-block, 13 to 18 are the p-block and the two rows at the bottom are the f-block.
The reaction is zero order in [A].
Doubling [A] from 0.10 mol·L⁻¹ to 0.20 mol·L⁻¹ has no effect on the initial rate.
