Answer:
2
Step-by-step explanation:
The "average value of function f(x) on interval [a, b] is given by:
f(b) - f(a)
ave. value = ---------------
b - a
Here f(t)=(t-2)^2.
Thus, f(b) = (b - 2)^2. For b = 6, we get:
f(6) = 6^2 - 4(6) + 4, or f(6) = 36 - 24 + 4 = 16
For a = 0, we get:
f(0) = (0 - 2)^2 = 4
Plugging these results into the ave. value function shown above, we get:
16 - 4
ave. value = ------------ = 12/6 = 2
6 - 0
The average value of the function f(t)=(t-2)^2 on [0,6] is 2.
Answer:
h(2)+g(2) = -3
Step-by-step explanation:
Replace the variable (t) with (
2) in the expression.
h (2) = 3 - 5
Replace the variable (t) with (
2) in the expression.
g(2) = 2(2) -5
Replace the function designators in h(2) +g(2) with the actual functions.
h(t) = 3 - 5 +2 (2) ← plug h(2) into 2(t)
Remove parentheses.
3 - 5 + 2(2)
Multiply 2 by 2
3 - 5 + 4 - 5
Subtract 5 from 3
.
-2 + 4 - 5
Add -2 and 4
2 - 5
Subtract 5 from 2
-3
Answer:
$9,000.00 is her original investment worth in 10 yrs.
5000 x 1.08 ^10 = 10794.6249864
Then subtract -500000 = 5794.62498636
Step-by-step explanation:
Why, because the first year is proved 5000 x 0.08 = 400
= 400 year 1 but cna keep only if stays in investment for 10 years
400 x 10 = 4000 interest on investment
5000+ 4000 = $9,000.00 SI
+ 1,794.62 Interest on interest if applies (this is called CI) and makes $10794.62
By definition we have that the average rate of change is given by:
AVR = (f (x2) - f (x1)) / (x2 - x1)
Substituting the values we have:
AVR = (204 - (-6)) / (10 - 0)
Rewriting we have:
AVR = (204 + 6) / (10 - 0)
AVR = 210/10
AVR = 21
Answer:
the average rate of change for f (x) from x = 0 to x = 10 is:
AVR = 21
