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2 years ago

C + 2H2 -> CH4

Chemistry

2 answers:

Pavel [41]2 years ago

6 0

Moles of methane

Given mass/Molar Mass
32/16
2mol

2moles hydrogen required for 1 mol CH_4 production

For 2 mol CH_4

Moles of H_2=2(2)=4

Option C

ankoles [38]2 years ago

4 0

Answer:

C) 4

Explanation:

The reaction :

C (s) + 2H₂ (g) ⇒ CH₄ (g)

12g 4g 16g

Hence, based on this we can say that : 2 moles of hydrogen gas are needed to produce 16g of methane.

For 32g of methane

Number of moles of H₂ = 32/16 × 2
Number of moles of H₂ = 4

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The empirical formula of a compound is CH. At 200 degree C, 0.145 g of this compound occupies 97.2 mL at a pressure of 0.74 atm.

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Answer:

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Explanation:

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The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

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Considering,

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Using ideal gas equation as:

$PV=\frac{m}{M}RT$

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V is the volume

m is the mass of the gas

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$0.74\times 0.0972=\frac{0.145}{M}\times 0.0821\times 473.15$

$M=78.31\ g/mol$

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Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,

Molecular mass = n × Empirical mass

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Mass from the Empirical formula = 12 + 1 = 13 g/mol

Molar mass = 78.31 g/mol

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Molecular mass = n × Empirical mass

78.31 = n × 13

⇒ n ≅ 6

The molecular formula = $C_{6}H_{6}$

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