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docker41 [41]
3 years ago
11

For a process at constant pressure, 12,400 calories of heat are released. this quantity of heat is equivalent to

Physics
1 answer:
Vinvika [58]3 years ago
6 0

Answer:

51,882 J

Explanation:

In order to convert the heat from calories to joule, we must remember the conversion factor:

1 cal = 4.184 J

Keeping in mind this, we can set up a proportion to find how much Joules correspond to 12,400 calories:

1 cal : 4.184 J = 12,400 cal : x\\x=\frac{(4.184 J)(12400 cal)}{1 cal}=51,882 J

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According to Georgia State University, gravitational potential energy<span> is the energy an object possesses because of its position in a gravitational field. This is most commonly in reference to an object near the surface of the Earth, where the gravitational acceleration is assumed to be constant at about 9.8 m/s2.</span>
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An object is thrown with a horizontal velocity of 20 m/s from a cliff that is 125 m above level ground. If air resistance is neg
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Given that,

Horizontal velocity of the object, v = 20 m/s

Height of the cliff, h = 125 m

We need to find the time that it takes the object to fall to the ground from the cliff is most nearly. It can be calculated using second equation of motion. Let us consider that the initial speed of the object is 0. So,

h=ut+\dfrac{1}{2}at^2

Here, a = g and u = 0

h=\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\times 125}{10}} \\\\t=5\ s

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3 years ago
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A series AC circuit contains a resistor, an inductor of 220 mH, a capacitor of 5.50 μF, and a generator with ΔVmax = 240 V opera
ki77a [65]

Answer:

Xl=wL=69.11503383 ohm

Xc=\frac{-1}{wC}= -578.7452476 ohm

Z=\frac{240}{140*10^-3}=1.714285714 kilo-ohm

R=2.223915928 kilo-ohm

\alpha = -12.90698798 centigrades

Explanation:

L=220*10^-3

C=5.50*10^-6

Vmax=240V

Imax=140*10^-3

w=2\pi f=2\pi *50=314.1592654

The capacitive reactance is given by:

Xc=\frac{-1}{wC}=-578.7452476 ohm

Now,  The inductive reactance is given by:

Xl=wL=69.11503383 ohm

By the ohm´s law, the electrical impedance is:

V=IZ

So

Z=\frac{V}{I}

Z=\frac{240}{140*10^-3}=1.714285714 kilo-ohm

The total impedance is:

Z=R+jX\\\\ (*)

Where X is the total reactance given by:

X=Xl+Xc=69.11503383-578.7452476=-509.6302138

Let´s calculate the real part of Z using (*):

R=1714.285714+509.6302138

R=2.223915928 kilo-ohm

Finally the angle between the current and the voltage is equal to the impedance angle:

\alpha=arctan(\frac{-509.6302138}{2223.915928})

\alpha =-12.90698798 centigrades

8 0
3 years ago
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