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Temka [501]
3 years ago
11

Which electromagnetic waves have a higher frequency than visible light

Physics
1 answer:
kenny6666 [7]3 years ago
7 0

The ones that we call 'ultraviolet', 'X-rays', and 'gamma rays' all have
higher frequency (shorter wavelength) than visible light.


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What is the period of a wave with a speed of 20.0 m/s and a frequency of 10.0 Hz?
Delvig [45]

<em>im confused hold on imma send you a link to the answer</em>Explanation:

4 0
3 years ago
Air friction damps a tuning fork so the amplitude decreases by 1/10 per second. Resonances] 10 Hz. what % chnge in frequency res
aleksandr82 [10.1K]

Answer:

The percentage change in frequency is 10%.

Explanation:

Given that,

Amplitude decreases by 1/10 per second.

Resonance = 10 Hz

We need to calculate the change in frequency

Using formula of change in frequency

\Delta f=\Delta A\times R

Put the value into the formula

\Delta f=\dfrac{1}{10}\times10

\Delta f=1\ Hz

We need to calculate the resonant frequency

Using formula of resonant frequency

f_{r}=R-\Delta f

Put the value into the formula

f_{r}=10-1

f_{r}=9\ Hz

We need to calculate the percentage change in frequency

Using formula of percentage change in frequency

f=\dfrac{10-9}{10}

f=10\%

Hence, The percentage change in frequency is 10%.

7 0
4 years ago
An ice skater spinning with outstretched arms has an angular speed of 5.0 rad/s . She tucks in her arms, decreasing her moment o
Artyom0805 [142]

Answer:

  K_{f} / K₀ =1.12

Explanation:

This problem must work using the conservation of angular momentum (L), so that the moment is conserved in the system all the forces must be internal and therefore the torque is internal and the moment is conserved.

Initial moment. With arms outstretched

         L₀ = I₀ w₀

the wo value is 5.0 rad / s

final moment. After he shrugs his arms

         L_{f} = I_{f}  w_{f}

indicate that the moment of inertia decreases by 11%

        I_{f} = I₀ - 0.11 I₀ = 0.89 I₀

        L_{f} = L₀

        I_{f} w_{f}  = I₀ w₀

        w_{f} = I₀ /I_{f}    w₀

let's calculate

        w_{f} = I₀ / 0.89 I₀   5.0

        w_{f} = 5.62 rad / s

Having these values ​​we can calculate the change in kinetic energy

         K_{f} / K₀ = ½ I_{f} w_{f}² (½ I₀ w₀²)

         K_{f} / K₀ = 0.89 I₀ / I₀ (5.62 / 5)²

         K_{f} / K₀ =1.12

6 0
3 years ago
When ultraviolet light with a wavelength of 400.0 nm falls on a certain metal surface, the maximum kinetic energy of the emitted
Andru [333]

Answer:

Explanation:

energy of photon having wavelength of 400 nm = 1237.5/400 eV

= 3.1 eV.

Maximum kinetic energy of photoelectrons = 1.1 eV .

Threshold energy Ф = 3.1 - 1.1 = 2 eV .

energy of photons having wavelength of 310 nm = 1237.5 / 310 eV = 4 eV .

Maximum kinetic energy of photoelectrons = energy of photons - Threshold energy

= 4 - 2 = 2 eV .

Required kinetic energy K₀= 2 eV.

8 0
3 years ago
Explain the significance of kelvin temperature scole.​
Marrrta [24]

Answer:

The Kelvin temperature scale is used by scientists because they wanted a temperature scale where zero reflects the complete absence of thermal energy. ... Many quantum mechanical properties are washed out by the thermal agitation that occurs in materials.

3 0
3 years ago
Read 2 more answers
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