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Brut [27]
3 years ago
5

An object is thrown with a horizontal velocity of 20 m/s from a cliff that is 125 m above level ground. If air resistance is neg

ligible, the time that it takes the object to fall to the ground from the cliff is most nearly
Physics
1 answer:
Serjik [45]3 years ago
5 0

Given that,

Horizontal velocity of the object, v = 20 m/s

Height of the cliff, h = 125 m

We need to find the time that it takes the object to fall to the ground from the cliff is most nearly. It can be calculated using second equation of motion. Let us consider that the initial speed of the object is 0. So,

h=ut+\dfrac{1}{2}at^2

Here, a = g and u = 0

h=\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\times 125}{10}} \\\\t=5\ s

So, the object will take 5 seconds to fall to the ground from the cliff.

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Practice entering numbers that include a power of 10 by entering the diameter of a hydrogen atom in its ground state, dH = 1.06
Slav-nsk [51]

Answer:

1.06085\times 10^{-10}\ m

Explanation:

h = Planck's constant = 6.626\times 10^{-34}\ m^2kg/s

m = Mass of electron = 9.11\times 10^{-31}\ kg

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

e = Charge of electron = 1.6\times 10^{-19}\ C

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Angular momentum is given by

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From Bohr's atomic model we have

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mvr=\dfrac{nh}{2\pi}\\\Rightarrow v=\dfrac{nh}{2\pi mr}

The centripetal force will balance the electrostatic force

\dfrac{ke^2}{r^2}=\dfrac{mv^2}{r}\\\Rightarrow \dfrac{ke^2}{r}=mv^2\\\Rightarrow \dfrac{ke^2}{r}=m(\dfrac{nh}{2\pi mr})^2\\\Rightarrow r=\dfrac{n^2h^2}{4\pi^2mke^2}\\\Rightarrow r=\dfrac{1^2\times (6.626\times 10^{-34})^2}{4\pi^2 \times 9.11\times 10^{-31}\times 8.99\times 10^{9}\times (1.6\times 10^{-19})^2}\\\Rightarrow r=5.30426\times 10^{-11}\ m

The diameter is 2\times 5.30426\times 10^{-11}=1.06085\times 10^{-10}\ m

7 0
3 years ago
Use the mass spectrum of europium to determine the atomic mass of europium. where the peak representing eu-151 has an exact mass
slavikrds [6]

Answer: The atomic mass of a Europium atom is 151.96445 amu.

From the given information:

Percent intensity is 91.61% of Europium atom of molecular weight 150.91986 amu.

Percent intensity is 100.00% of Europium atom of molecular weight 152.92138 amu.

Abundance of Eu-151 atom:

X_{Eu-151}=\frac{0.9161}{0.9161+1.000}=0.4781

Abundance of Eu-153 atom:

X_{Eu-153}=\frac{1.000}{0.9161+1.000}=0.5219

Atomic mass of Europium atom:

A=(X_{Eu-151}\times150.91986+X_{Eu-153}\times152.92138)amu\\A=(0.4781\times150.91986+0.5219\times152.92138)amu=151.96445 amu

Therefore, the atomic mass of a Europium atom is 151.96445 amu.

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Answer:

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hope it helps

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