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koban [17]
3 years ago
8

Cual de los elementos no metaleses el menos reactivo? ​

Chemistry
1 answer:
Fittoniya [83]3 years ago
3 0

Answer:

UUMMMM ENGLESS POR FAVORS

Explanation:

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Combustion reactions are exothermic. The heat of reaction for the combustion of 2-methylheptane, C8H18, is 1.306×103 kcal/mol. W
WARRIOR [948]

Answer:

11.45kcal/g

2.612 × 10³ kcal

Explanation:

When a compound burns (combustion) it produces carbon dioxide and water. The combustion of 2-methylheptane can be represented by the following balanced equation:

2 C₈H₁₈ + 25 O₂ ⇄ 16 CO₂ + 18 H₂O

It releases  1.306 × 10³ kcal every 1 mol of C₈H₁₈ that is burned.

<em>What is the heat of combustion for 2-methylheptane in kcal/gram?</em>

We know that the molar mass of C₈H₁₈ is 114.0g/mol. Then, using proportions:

\frac{1.306 \times 10^{3}Kcal}{1mol} .\frac{1mol}{114.0g} =11.45kcal/g

<em>How much heat will be given off if molar quantities of 2-methylheptane react according to the following equation? 2 C₈H₁₈ + 25 O₂ ⇄ 16 CO₂ + 18 H₂O</em>

In this equation we have 2 moles of C₈H₁₈. So,

2mol \times\frac{1.306 \times 10^{3}kcal }{1mol} =2.612\times 10^{3}kcal

3 0
3 years ago
NH4Cl and Na2CO3<br> Balanced Equation<br> Total Ionic Equation<br> Net Ionic Equation
Ymorist [56]

Answer:

a) <u>Balanced Equation</u>

2NaCl (aq) + (NH₄)₂CO₃ (aq)  →   Na₂CO₃ (aq) + 2NH₄Cl (aq)

b)  <u>Total Ionic Equation</u>

2Na⁺ (aq) + 2Cl⁻ (aq) + 2NH₄⁺ (aq) + CO₃ ²⁻ (aq)   →   2Na⁺ (aq) + CO₃²⁻ (aq) + 2NH₄⁺ (aq) + 2Cl⁻ (aq)

c) <u>Net Ionic Equation</u>

All are spectator ions, so no net ionic equation.

5 0
3 years ago
Read 2 more answers
Which of the following statements is true of vibrations? A. The frequency of infrasonic vibrations is much too high to be heard
Wewaii [24]

D. ( Neither ultrasonic nor infrasonic vibrations can be heard by humans. )

4 0
3 years ago
Read 2 more answers
Please help with this
zhenek [66]
Im guessing it would be 3.53 × 1023 atoms
5 0
3 years ago
How many grams of a solution that is 5.2% sucrose by mass are needed to obtain 18g of sucrose
kirill115 [55]

Answer:

346.g of solution

Explanation:

In this case, if we have 5.2 % by mass it means that in <u>100 g of the solution we will have 5.2 g of glucose</u>. Therefore we can do the calculation:

<u>5.2 g of glucose = 100 g of solution</u>

18~g~of~glucose\frac{100~g~of~solution}{5.2~g~of~glucose}=346.15~g~of~solution

So, if we need 8 g of glucose we had to have 346.15 g of solution

This logic can work for all types of solutions. By mass (as in this case), by volume or mass/volume.

I hope it helps!

3 0
4 years ago
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