Answer:
Area segment = 3/2 π - (9/4)√3 units²
Step-by-step explanation:
∵ The hexagon is regular, then it is formed by 6 equilateral Δ
∵ Area segment = area sector - area Δ
∵ Area sector = (Ф/360) × πr²
∵ Ф = 60° ⇒ central angle of the sector
∵ r = 3
∴ Area sector = (60/360) × (3)² × π = 3/2 π
∵ Area equilateral Δ = 1/4 s²√3
∵ The length of the side of the Δ = 3
∴ Area Δ = 1/4 × (3)² √3 = (9/4)√3
∴ Area segment = 3/2 π - (9/4)√3 units²
Answer:
A. C.
Step-by-step explanation:
The correct answer would be C., I believe, because you take the opposite of the coordinate and subtract one. Hope this was helpful! (:
Answer:
When t=2.1753 & t=.5746 , h=27
Don't worry, I got you. Also, my calculator does too.
We set h equal to 27, because we want the height to be 27 when we solve for t.
That leaves us with:
27 = 7 + 44t - 16t^2
Simplify like terms,
20 = 44t - 16t^2
Move 20 onto the right side, so we can use quadratic equation
44t - 16t^2 - 20 = 0 --> -16t^2 + 44t - 20
Using quadratic, you get
t=2.1753 & t=.5746
<u>poster confirmed : "It’s t=2.18 and t=0.57"</u>
Seems to be an arythmetic sequence
Sn=[n(a1+an)]/2
where
Sn means sum of all terms up the nth term
n=number of terms
a1=first term
an=nth term
so from 86 to the 22th term is from a1 to a22
find teh sequence
miknus 7 each time
an=a1+d(n-1)
an=87-7(n-1)
find 22n term
a22=87-7(22-1)
a22=87-7(21)
a22=87-147
a22=-60
S22=[22(87-60)]/2
S22=[22(27)]/2
S22=594/2
S22=297
the sum is 297
