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Effectus [21]
3 years ago
8

3 1/3 - 1 2/3 = ? Help me plzz i beg you i lost my notes :(

Mathematics
2 answers:
tamaranim1 [39]3 years ago
8 0
You turn them into improper fractions by multiplying the bottom number to the whole number then adding the product to the top of the fraction, therefore 
3 1/3 = 10/3, and 1 2/3 = 5/3

10 _ 5  =  5/3
 3     3
Dmitriy789 [7]3 years ago
6 0
That equals to 2 1/3
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For the circle with equation (x-2)^2+(y+3)^2=9, answer each question. a) whats coords of the center? b) what are the radius and
MrRissso [65]

Answer:

<h2>a) center (2, -3)</h2><h2>b) radius r = 3</h2><h2>c) in the attachment</h2>

Step-by-step explanation:

The standard form of an equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have:

(x-2)^2+(y+3)^2=9\\\\(x-2)^2+(y-(-3))^2=3^2

a) center (2, -3)

b) radius r = 3

c) in the attachment

4 0
3 years ago
Im going to say this right now please stop giving me answers from other links or ones that have been copied your answer can be r
enot [183]

Answer:

D. Collinear

Step-by-step explanation:

Three points lying on a line are collinear because they share the same line.

the rest of the options can be ruled out because the points can not be congruent due to lack of distance information and the same goes for midpoint and equal.

3 0
3 years ago
Please help! What is 9.6=1/2b show work please!
o-na [289]

Answer:

b = 19.2

Step-by-step explanation:

9.6 = ½b

=> 9.6 × (2/1) = b

=> 9.6 × 2 = b

=> 19.2 = b

8 0
2 years ago
Write the expression using a single exponent 2^2•2^8
kondor19780726 [428]

I think it’s C. 4^16,

5 0
3 years ago
A force of F pounds is required to pull an object weighing W pounds up a ramp inclined at θ degrees from the horizontal. Find θ
Pie

Answer:

The value of θ is 20.105°

Step-by-step explanation:

Consider the provided information.

A force of F pounds is required to pull an object weighing W pounds up a ramp inclined at θ degrees from the horizontal.

Sine of angle is force over weight.

\sin\theta=\frac{F}{W}

Substitute F = 5500 pounds and W = 16,000 pounds in above formula.

\sin\theta=\frac{5500}{16000}

\sin\theta=\frac{11}{32}

\theta\approx20.105

Hence, the value of θ is 20.105°

5 0
3 years ago
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