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Nady [450]
2 years ago
11

Find the mode for the scores 3,760, 5,200, 8,750, 4,400, 5,250

Mathematics
1 answer:
Semenov [28]2 years ago
8 0
There is no mode in these scores.

This is because mode is when two numbers show up the same like 4 and 4.
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Calculate the length of the side BC. Using pythagoras ​
o-na [289]

Answer:

10m

Step-by-step explanation:

<em><u>A^2+B^2=C^2</u></em>

<em><u>6^2+8^2=C^2</u></em>

36+64=C^2

100=C^2

10=C

3 0
3 years ago
Read 2 more answers
I need the answer fast please
shusha [124]
The diameter of the circle is needed. But to solve, you would simply multiply the diameter of the circle by pi (3.14).
3 0
3 years ago
Solve for t if p≠q<br> (t+p)/q - q/p = (t-q)/p + p/q
german

Answer:

.. q T 0 = (q/p)a (q/p)a − (q/p)T−10 if p ≠ q and qT0 = 1 − T0/a if p = q = 1/2.

Step-by-step explanation:

Suppose that there are two different solutions, p and q, in [a, b]. Thus p =g(p) q =g(q) p ≠ q The function g(x) satisfies the hypotheses of the mean-value ... that g(p) –g(q) = (p – q) g׳(t) Because g(p) =p and g(q) = q, the left side of Eq. (1-3) may...

6 0
3 years ago
3/9=21/k what is the strategy for solving it
Vinvika [58]

Answer: k = 63

Step-by-step explanation: You need to multiply the left side by its reciprocal to move the numbers to the right. You also need to multiply by k on the right side to get it alone on the left. This will result in

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1 = 189/3k • k    then multiply by k

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k = 63

5 0
3 years ago
Triangle inequality theorem-are the lengths 7, 4, and 2 of a triangle possible?
kakasveta [241]

You can't make a triangle with those lengths for sides.

The way I look at it is like this:

-- Take  2  sticks ... lengths  4  and  2  ... and connect them together at one end.

-- The farthest they can reach, if they're opened up completely and pointing
in opposite directions, is a distance of  6 .

-- They can't reach the ends of a stick that is  7  long.  So you can't make
a triangle with those  3  sticks.


6 0
4 years ago
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