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algol [13]
3 years ago
8

Roderick wants to draw a circle for which the numerical value of the circumference is greater than the value of the area. Which

lengths could he use for the radius? Select three options. One-half 1 1.5 2 2 and one-half
Mathematics
2 answers:
sergiy2304 [10]3 years ago
6 0

Answer:

One-half

1

1.5

Step-by-step explanation:

Area of a circle = πr²

The circumference of a circle = 2πr

n = 3.14

r = radius

Where : = π = pi = 22/7

R = radius

when radius is 1/2

Area = π  x (1/2)^2 = 0.25π

circumference = 2π (1/2) = 1

the circumference is greater than the value of the area

when radius is 1 1/2

Area = π  x (1 1/2)^2 = 2.25π

circumference = 2π ( 1 1/2) = 3

the circumference is greater than the value of the area

when radius is 1

Area = π  x (1 )^2 = 1π

circumference = 2π ( 1) = 2

the circumference is greater than the value of the area

when radius is 2

Area = π  x (2 )^2 = 4π

circumference = 2π ( 2) = 4

circumference equals area

makkiz [27]3 years ago
3 0

Answer:

A, B, C

Step-by-step explanation:

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X (squared=9 what is x
yarga [219]
X is 3 because 3 sqaured is 3x3=9
6 0
4 years ago
Give the set of four quantum numbers that represent the last electron added (using the aufbau principle to the cl atom.
qaws [65]
An element has four quantum numbers associated with it. We have

1. principal quantum number (n)
2. azimuthal quantum number (l)
3. magnetic quantum number (m_{l})
4. spin quantum number (m_{s})

To look for each quantum  number of Chlorine (Cl), we mus first recall its electronic configuration: 1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}.

1. For n, we need to look for its highest energy level or by simply checking the period that the element belongs to. So for this case, it's n = 3.

2. For l, we need to look for the sublevel where the last electron was assigned. The sublevels, p, d, f are assigned to a value of 0, 1, 2, and 3, respectively. Since the last electron was assigned in p, then l = 1.

3. And for m_{l}, the number of orbitals present in Cl is 2l+1 = 3. The possible magnetic quantum numbers for p are -1, 0, +1. Since there 5 electrons we count starting at -1. So, we have m_{l}=+1[tex].\\4.  Lastly, for [tex]m_{s}, we need to determine the spin. Since we have 5 electrons, all the arrows upward are filled in. That means the fifth electron has a spin of +1/2. 

Answers: n =3, l = 1, m_{l} = 0, m_{s} =+1/2


8 0
3 years ago
Help plz
tensa zangetsu [6.8K]

The answer is 117 inches^3

Please see the attached picture for full solution

Hope it helps

Good luck on your assignment

8 0
3 years ago
Read 2 more answers
Consider the relation.
Anit [1.1K]

{(–3, 2), (–1, 3), (–1, 2), (0, 4), (1, 1)}

Answer:

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4 0
3 years ago
How do you solve 1-(6-3)
atroni [7]

Answer:

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Step-by-step explanation:

1-(6-3)

<em>multiply the negative into the bracket so it becomes</em>

= 1-6+3

= -2

4 0
3 years ago
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