Roderick wants to draw a circle for which the numerical value of the circumference is greater than the value of the area. Which
2 answers:
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Answer:
The scale factor of the smaller rectangle to the larger rectangle is 3/2
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor
In this problem
To find out the scale factor of the smaller rectangle to the larger rectangle. set up a proportion
----> ratio of corresponding heights
or
----> ratio of corresponding bases
therefore
The scale factor of the smaller rectangle to the larger rectangle is 3/2
Answer:
(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.
(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.
(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.
Step-by-step explanation:
Let <em>X</em> = number of seconds in the batch.
The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.
The probability mass function of <em>X</em> is:
(a)
Compute the probability that only one goblet is a second among six randomly selected goblets as follows:
Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.
(b)
Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:
P (X ≥ 2) = 1 - P (X < 2)
Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.
(c)
If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.
P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)
Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.