Answer:
18 g
Explanation:
We'll begin by converting 500 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
500 mL = 500 mL × 1 L / 1000 mL
500 mL = 0.5 L
Next, we shall determine the number of mole of the glucose, C₆H₁₂O₆ in the solution. This can be obtained as follow:
Volume = 0.5 L
Molarity = 0.2 M
Mole of C₆H₁₂O₆ =?
Molarity = mole / Volume
0.2 = Mole of C₆H₁₂O₆ / 0.5
Cross multiply
Mole of C₆H₁₂O₆ = 0.2 × 0.5
Mole of C₆H₁₂O₆ = 0.1 mole
Finally, we shall determine the mass of 0.1 mole of C₆H₁₂O₆. This can be obtained as follow:
Mole of C₆H₁₂O₆ = 0.1 mole
Molar mass of C₆H₁₂O₆ = (12×6) + (1×12) + (16×6)
= 72 + 12 + 96
= 180 g/mol
Mass of C₆H₁₂O₆ =?
Mass = mole × molar mass
Mass of C₆H₁₂O₆ = 0.1 × 180
Mass of C₆H₁₂O₆ = 18 g
Thus, 18 g of glucose, C₆H₁₂O₆ is needed to prepare the solution.
In the compound nh3, nitrogen has an oxidation number of 3+ and hydrogen has an oxidation number of -1
The molecule NH3 have a neutral charge so the number of oxidation number of it's component must be equal to zero. The molecule NH composed of 1 nitrogen and 3 hydrogens. If the nitrogen oxidation number is 3+, then hydrogen would be:
1* N + 3*H=0
1*+3 +3*H=0
3H= -3
H= -1
Answer:
7 chlorine atoms
Explanation:
K=2.8.8.1
Cl=2.8.7
pottasium will give chlorine its I valence electron to form ions as follows
K=(2.8.8)+
Cl=(2.8.8)-
The answer to this is true.
