Answer:
Approximately 
(approximately 
) assuming that the magnetic field and the wire are both horizontal.
Explanation:
Let 
denote the angle between the wire and the magnetic field.
Let 
denote the magnitude of the magnetic field.
Let 
denote the length of the wire.
Let 
denote the current in this wire.
The magnetic force on the wire would be:
.
Because of the 
term, the magnetic force on the wire is maximized when the wire is perpendicular to the magnetic field (such that the angle between them is 
.)
In this question:
(or, equivalently, 
radians, if the calculator is in radian mode.)
.
.
.
Rearrange the equation 
to find an expression for , the current in this wire.
.
Here we have been given two charged body W and X.
We are asked to determine the nature of charge.
Before coming into conclusion, first we have to understand the electric field lines.
The electric field lines are pictorial representation of imaginary lines which are drawn to denote the electric field in a graphical way.
The electric field line starts from a positive charge and ends at a negative charge.It means for positive charges the electric field lines are outward and for negative charges the filed lines will be inward.
In the given diagram,the filed lines for W is towards W itself.The same is also in case of X.
Hence both the charges must be negative in nature.
Hence the correct answer to the question will be B i.e W negative and X: NEGATIVE.
Distance = 1/2*gravity*velocity^2
<span>So plugging: 1/2 * 9.8 * 25 = 122.5units
and is six second
</span><span>Distance = 1/2*gravity*velocity^2
</span><span>So plugging: 1/2 * 9.8 * 36= 176.4 units</span>
Answer:
16.63min
Explanation:
The question is about the period of the comet in its orbit.
To find the period you can use one of the Kepler's law:
T: period
G: Cavendish constant = 6.67*10^-11 Nm^2 kg^2
r: average distance = 1UA = 1.5*10^11m
M: mass of the sun = 1.99*10^30 kg
By replacing you obtain:
the comet takes around 16.63min
