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Crazy boy [7]
3 years ago
6

Need help on nubmer 2 plz

Mathematics
1 answer:
4vir4ik [10]3 years ago
5 0

im sorry but I don't understand what its asking


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Help me plz with this I need help
marysya [2.9K]
How are we supposed to help with this what the heck??
4 0
3 years ago
PLEASE HELP DUE TONIGHT! 100 PTS
Naily [24]

Answer:

a. $15.00

b. $15.00

c. they earn the same. If you divide Carl's hours by the amount of time he works, for instance, 45÷3=15, you get 15 for all of them. They earn the same.

7 0
2 years ago
Read 2 more answers
Some people think it is unlucky if the 13th day of month falls on a Friday. show that in that there year (non-leap or leap) ther
Vlad1618 [11]
<span>There are several ways to do this problem. One of them is to realize that there's only 14 possible calendars for any year (a year may start on any of 7 days, and a year may be either a leap year, or a non-leap year. So 7*2 = 14 possible calendars for any year). And since there's only 14 different possibilities, it's quite easy to perform an exhaustive search to prove that any year has between 1 and 3 Friday the 13ths. Let's first deal with non-leap years. Initially, I'll determine what day of the week the 13th falls for each month for a year that starts on Sunday. Jan - Friday Feb - Monday Mar - Monday Apr - Thursday May - Saturday Jun - Tuesday Jul - Thursday Aug - Sunday Sep - Wednesday Oct - Friday Nov - Monday Dec - Wednesday Now let's count how many times for each weekday, the 13th falls there. Sunday - 1 Monday - 3 Tuesday - 1 Wednesday - 2 Thursday - 2 Friday - 2 Saturday - 1 The key thing to notice is that there is that the number of times the 13th falls upon a weekday is always in the range of 1 to 3 days. And if the non-leap year were to start on any other day of the week, the numbers would simply rotate to the next days. The above list is generated for a year where January 1st falls on a Sunday. If instead it were to fall on a Monday, then the value above for Sunday would be the value for Monday. The value above for Monday would be the value for Tuesday, etc. So we've handled all possible non-leap years. Let's do that again for a leap year starting on a Sunday. We get: Jan - Friday Feb - Monday Mar - Tuesday Apr - Friday May - Sunday Jun - Wednesday Jul - Friday Aug - Monday Sep - Thursday Oct - Saturday Nov - Tuesday Dec - Thursday And the weekday totals are: Sunday - 1 Monday - 2 Tuesday - 2 Wednesday - 1 Thursday - 2 Friday - 3 Saturday - 1 And once again, for every weekday, the total is between 1 and 3. And the same argument applies for every leap year. And since we've covered both leap and non-leap years. Then we've demonstrated that for every possible year, Friday the 13th will happen at least once, and no more than 3 times.</span>
5 0
3 years ago
How can you use 4×7 to find 8×7
Natasha_Volkova [10]
If you think about it, 4x7 is half of 8x7 (If you multiply 4, 7, and 2, you get 8x7). So really you can just multiply 4x7 by 2 and you will get 8x7!
7 0
2 years ago
Read 2 more answers
8.4×0.5 showing work​
Katen [24]
Can u add a picture?
8 0
2 years ago
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