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tangare [24]
3 years ago
12

The weekly salary y of an individual is proportional to the number of hours x worked. A person who works 40 hours is paid $900.

Write an equation that represents the situation. Then determine how many hours the individual worked if the amount paid is $630.
Mathematics
1 answer:
____ [38]3 years ago
4 0
The individual should work 28 hours to earn $630 at a rate of $22.50 per hour.

Direct variation formula is y = kx;
Where y directly varies on the changes of x with the constant ratio of k.

We need to first get the k or constant rate.

y = kx
900 = k (40)
k = 900 / 40
k = 22.50 this is the rate per hour

To check:

900 = 22.50 * 40
900 = 900

y = 22.50x
630 = 22.50x
x = 630 / 22.50
x = 28 hours.

To check:

630 = 22.50 * 28
630 = 630
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F(n) = f(n – 1) + f(n – 2); f(1) = 2; f(2) = 1.
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f(n) is the nth term

Each term f(n) is found by adding the terms just prior to the nth term. Those two terms added are f(n-1) and f(n-2)

The term just before nth term is f(n-1)

The term just before the (n-1)st term is f(n-2)

----------------

For example, let's say n = 3 indicating the 3rd term

n-1 = 3-1 = 2

n-2 = 3-2 = 1

So f(n) = f(n-1) + f(n-2) turns into f(3) = f(2) + f(1). We find the third term by adding the two terms just before it.

f3) = third term

f(2) = second term

f(1) = first term

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3 years ago
Which statement about the function Y equals X2 +5 is correct
iVinArrow [24]

Answer: what are the options?

Step-by-step explanation:

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PLS HELP ME. im desperateeeeeee uwu
Anna007 [38]

Answer:

Greetings!

The answer to the first image is: 3\sqrt{6}

The second image is 4\sqrt{3}

Step-by-step explanation:

Here's how to rationalize a denominator:

1. Multiply numerator and denominator by a radical that will get rid of the radical in the denominator.

2. Make sure all radicals are simplified.

3. Simplify the fraction if it is needed.

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8 0
2 years ago
I need help finding the range and domain, you can use the images I've included for guidance! I need this asap thank youu
SCORPION-xisa [38]

Answer:

\displaystyle Range: \\ Set-Builder\:Notation → y|1 ≥ y ≥ -1 \\ Interval\:Notation → [-1, 1] \\ \\ Domain: \\ Set-Builder\:Notation → x|x ∈ R \\ Interval\:Notation → (-∞, ∞)

Step-by-step explanation:

This is the graph of \displaystyle y = cos\:x,in which its AMPLITUDE [<em>A</em>] ALWAYS starts ONE BLOCK ABOVE the <em>midline</em><em>.</em><em> </em>In the trigonometric formula below, −C gives the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

\displaystyle y = Acos[Bx - C] + D

NOTE: Depending on how your trigonometric graphs are structured, your vertical shift [<em>D</em>] might tell you to space out the amplitude of the graphs alot more evenly on both ends.

<u>Extended</u><u> </u><u>Information on</u><u> </u><u>Trigonometric</u><u> </u><u>Graphs</u>

\displaystyle Vertical\:Shift = D \\ Phase\:Shift\:[Horizontal\:Shift] = \frac{C}{B} \\ Period = \frac{2}{B}π \\ Amplitude = |A|

I am joyous to assist you anytime.

7 0
3 years ago
P L E A S E HELP FAST 30 POINTS
kramer
The answer to the question is b
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