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4 years ago

Help please I'm rather horrible at math.

Mathematics

2 answers:

Alja [10]4 years ago

6 0

Im not a hundred percent sure but i think it is 1 maybe sorry im not the best at this stuff

Triss [41]4 years ago

4 0

Two planes intersect at one line.
Take two sides of a cube. The sides of the cube meet at one edge. The sides are planes, while the edge is a line.

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Help me please! Don’t skup

scoundrel [369]

I won't skup.

We have an eight of a circle has area 9π sq in, so the total circle has area

πr² = 8(9π) = 72π

r² = 72 = 2(36)

r = 6√2 ≈ 8.485281374238571

Answer: A. 8.48 inches

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3 years ago

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The slope of the line?

Ostrovityanka [42]

The slope of this line is 3/2.

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4 years ago

What is 0.25 of 1000

andrew-mc [135]

2.5 is the answer for this

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3 years ago

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Complete the steps to find the value of x.<br> 2xº<br> 1282

andrew-mc [135]

Answer: 64°

Explanation: We know this because 2x=128, so if you divide 128/2 you’ll find x which is 64!

Hope this helps :)

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3 years ago

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The Laplace Transform of a function f(t), which is defined for all t > 0, is denoted by L{f(t)} and is defined by the imprope

lesya692 [45]

(1) D

$L_s\left\{t\right\} = \displaystyle\int_0^\infty te^{-st}\,\mathrm dt$

Integrate by parts, taking

$u = t \implies \mathrm du=\mathrm dt$

$\mathrm dv = e^{-st}\,\mathrm dt \implies v=-\dfrac1se^{-st}$

Then

$L_s\left\{t\right\} = \displaystyle \left[-\frac1ste^{-st}\right]\bigg|_{t=0}^{t\to\infty}+\frac1s\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{t\right\} = \displaystyle \frac1s\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{t\right\} = \displaystyle -\frac1{s^2}e^{-st}\bigg|_{t=0}^{t\to\infty}$

$L_s\left\{t\right\} = \displaystyle \boxed{\frac1{s^2}}$

(2) A

$L_s\left\{1\right\} = \displaystyle\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{1\right\} = \displaystyle\left[-\frac1se^{-st}\right]\bigg|_{t=0}^{t\to\infty}$

$L_s\left\{1\right\} = \displaystyle\boxed{\frac1s}$

7 0

3 years ago