All categories

3 years ago

Daniel bought a van for Rs258 750.This price included a VAT of 15%.Calculate the price of the van without VAT

Mathematics

2 answers:

ch4aika [34]3 years ago

8 0

Answer:

Step-by-step explanation:

price with vat=258750

VAT %=15%

let original price be x

CP+VAT%*CP= Rs258750

x+15/100*x= Rs258750

100x+15x= Rs258750*100

115x= Rs25875000

x= Rs25875000/115

x= Rs225000

iVinArrow [24]3 years ago

3 0

Step-by-step explanation:

is answer

Daniel bought a van for Rs258 750.This price included a VAT of 15%.Calculate the price of the van without VAT

You might be interested in

A set of 9 numbers has a mean of 20. What additional number must be included in this set to create a new set with a mean that is

PIT_PIT [208]

<em>Greetings from Brasil...</em>

The average for a set of 9 elements will be

(A + B + C + D + E + F + G + H + I) ÷ 9 = 20

Let's make (A + B + C + D + E + F + G + H + I) like S

<em>(I chose S to remember a sum)</em>

Let us think.....

S ÷ 9 = 20

S = 20 × 9

S = 180

So, (A + B + C + D + E + F + G + H + I) = 180

According to the statement, we will include a number (element J) in the sum to obtain a mean of (20 - 4), that is:

as seen above, (A + B + C + D + E + F + G + H + I) = 180, then

(180 + J) ÷ 10 = 16

(180 + J) = 160

J = 160 - 180

So, including the number - 20 <em>(minus 20)</em> in the original mean we will obtain a new mean whose result will be 16

3 0

3 years ago

Watcha help me now now nkw

Valentin [98]

Answer:

que mal

no te ayudare

por culpa de brailyn

Step-by-step explanation:

culpables

BRAILYN

CULPABLES

BUUUUUUUUU

FUERAAA MODERADORES

BUUUUUUUUUU

3 0

2 years ago

Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t

dmitriy555 [2]

Answer:

1. Find the difference between the areas.

<u>Area of the small rectangle</u>: $(x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14$

<u>Area of the big rectangle</u>: $(x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99$

The difference is: $11x+85$

$( x^2+20x+99)- (x^2+9x+14)=x^2+20x+99-x^2-9x-14=11x+85$

You can solve this question just by looking at the graph.

a) The height is 4 meters.

$f(d)=h=-2d^2+7d+4$

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

$f(0)=h=-2(0)^2+7(0)+4$

$h=4$

The height is 4 meters.

b) 9 meters.

For $d=1$

$f(1)=h=-2(1)^2+7(1)+4$

$f(1)=h=-2+7+4$

$h=9$

b) The ball travels 4 meters.

But to calculate it, it is when $h=0$

$0=-2d^2+7d+4$

Using the quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$

$d=\frac{-7\pm\sqrt{81}}{-4}$

$d=\frac{-7\pm9}{-4}$

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

The volume of a cylinder:

$V=\pi r^2h$

$V=\pi (2.5)^2 \cdot 5$

$V=31.25 \pi$

$V_{c} \approx 98.17 \text{ m}^3$

The volume of the sphere:

$V=\frac{4}{3} \pi r^2$

$V_{s} \approx 65.4 \text{ m}^3$

The volume of the capsule is approximately $163.57 \text{ m}^3$

3 0

3 years ago

What is the solution? pls help

loris [4]

Answer:

Solve by substitution

[y=5/2x-4]

[y= -x+3]

Substitute y = -x +3

[-x+3=5/2x-4]

Isolate x for -x+3=5/2x-4: x=2

For y = -x+3

Substitute x = 2

y= -2+3

Simplify

y=1

The solutions to the system of equations are:

y=1 x=2

3 0

2 years ago

Karina says every equilateral triangle is acute. Is this true explain

LenaWriter [7]

Yes, every equilateral triangle is acute because the angles are always congruent(identical) and 60 degrees which is acute. But I may be wrong. :P

5 0

3 years ago