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Vika [28.1K]
3 years ago
6

Before operating on an unfamiliar body of water why is it important to determine the location of shoaling areas

Physics
1 answer:
Blizzard [7]3 years ago
8 0
<span>It is important to determine their location before operating on an unfamiliar body of water because they are often difficult to spot, even with local charts. If you don't know what you're doing you can get stuck and that can be a huge problem, so it's necessary to know what you're doing and where they are located.</span>
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Two identical metal balls a and b are mounted on insulating rods. Ball a has a charge of +q/2 and ball b is initially uncharged.
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Help me please?

Explanation:

Did you get the answer? I believe it’s either C. +q or D. 0

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A gamma ray is pure __________. <br><br><br><br><img src="https://tex.z-dn.net/?f=%20u%5C%5C%20r%5C%5C%20cursed%5C%5C%20my%5C%5C
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A group of physics students hypothesize that for an experiment they are performing, the speed of an object sliding down an incli
goblinko [34]

Answer:

v = 2.974

Explanation:

Perhaps the formula should be

v = √(2*g*d (sin(θ) - uk*cos(θ) )                    This is a bit easier to read.

v = √(2* 9.80*0.725(0.707 - 0.12*0.707) )   Substitute values. Find 2*g*d

v = √14.21 * (0.707 - 0.0849)                        Figure out Sin(θ) - uk cos(θ)  

v = √14.21 * (0.6222)

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6 0
4 years ago
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A ball is dropped from a rooftop 60m high. <br> How long is the ball in the air?
alina1380 [7]

Answer: 3.49 s

Explanation:

We can solve this problem with the following equation of motion:

y=y_{o}+V_{o}t-\frac{1}{2}gt^{2} (1)

Where:

y=0 m is the final height of the ball

y_{o}=60 m is the initial height of the ball

V_{o}=0 m/s is the initial velocity (the ball was dropped)

g=9.8 m/s^{2} is the acceleratio due gravity

t is the time

Isolating t:

t=\sqrt{\frac{2 y_{o}}{g}} (2)

t=\sqrt{\frac{2 (60 m)}{9.8 m/s^{2}}} (3)

Finally we find the time the ball is in the air:

t=3.49 s (4)

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4 years ago
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