uppose the bottom block has a mass of 0.4 kg and the top block has a mass of 0.1 kg. What force do you need to exert (in newtons
1 answer:
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Hi there! :)
Use the following kinematic equation to solve for the final velocity:
In this instance, the runner started from rest, so the initial velocity is 0 m/s. We can rewrite the equation as:
Plug in the given acceleration and time:
Answer:
question5: F=74312.5N
question6: charge at the end of antenna=0.37N
Explanation:
Coulomb's law: the magnitude of the force of attraction or repulsion due to two charges is proportional to the product of the magnitude of the charges and inversely proportional to the square of distance between the charges.
⇒
∴
where is the force of attraction or repulsion
is Coulumb's constant=
and
are the magnitude of the charges
is the distance between two charges
The force between the two charges is attractive if they are of different polarity
The force between the two charges is repulsive if they are of same polarity
Question5:
Given: q1=0.041 C, q2=0.029 C, r=12 m
therefore by Coulumb's law,
Question6:
Given: q1=, r=5 m, F=
therefore by Coulumb's law,
⇒