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vova2212 [387]
4 years ago
12

The total energy in a closed system remains the same or changes as energy changes forms

Physics
1 answer:
lakkis [162]4 years ago
7 0

The total energy remains the same, as long as
none of it escapes the closed system.

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The potential energy between two atoms in a particular molecule has the form U(x) = 2.1 x 8 − 5.2 x4 where the units of x are le
a_sh-v [17]

Answer:

x\approx 0.948

Explanation:

The correct formula for the potential energy between two atoms in a particular molecule is:

U(x) = \frac{2.1}{x^{8}}-\frac{5.2}{x^{4}}

Where x is the distance.

According to the definitions of potential energy and work, as well as the Work-Energy Theorem and the Principle of Energy Conservation. The relation between that and related force is:

F = -\frac{dU}{dx}

The function is derived in terms of distance:

F (x) = \frac{84}{5\cdot x^{9}} -\frac{104}{5\cdot x^{5}}

Then, it is needed to find at least of x so that F(x) equals to 0.

\frac{84}{5\cdot x^{9}}-\frac{104}{5\cdot x^{5}}=0

\frac{84}{x^{4}}-104 = 0

84-104\cdot x^{4} = 0

x=\sqrt[4]{\frac{84}{104} }

x\approx 0.948

7 0
3 years ago
A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s.
kherson [118]

Answer:

<em>a. The rock takes 2.02 seconds to hit the ground</em>

<em>b. The rock lands at 20,2 m from the base of the cliff</em>

Explanation:

Horizontal motion occurs when an object is thrown horizontally with an initial speed v from a height h above the ground. When it happens, the object moves through a curved path determined by gravity until it hits the ground.

The time taken by the object to hit the ground is calculated by:

\displaystyle t=\sqrt{\frac{2h}{g}}

The range is defined as the maximum horizontal distance traveled by the object and it can be calculated as follows:

\displaystyle d=v.t

The man is standing on the edge of the h=20 m cliff and throws a rock with a horizontal speed of v=10 m/s.

a,

The time taken by the rock to reach the ground is:

\displaystyle t=\sqrt{\frac{2*20}{9.8}}

\displaystyle t=\sqrt{4.0816}

t = 2.02 s

The rock takes 2.02 seconds to hit the ground

b.

The range is calculated now:

\displaystyle d=10\cdot 2.02

d = 20.2 m

The rock lands at 20,2 m from the base of the cliff

5 0
3 years ago
Which of these experiments would make use of qualitative data?
Artyom0805 [142]
The answer is A study of different surfaces to compare ability to repel water. Hope this helps!
8 0
4 years ago
Read 2 more answers
Suppose you are at the center of a large freely-rotating horizontal turntable in a carnival funhouse. As you crawl toward the ed
I am Lyosha [343]

Answer:

c. remains the same, but the RPMs decrease.

Explanation:

Because there aren't external torques on the system composed by the person and the turntable it follows that total angular momentum (I) is conserved, that means the total angular momentum is a constant:

\overrightarrow{L}=constant

The total angular momentum is the sum of the individual angular momenta, in our case we should sum the angular momentum of the turntable and the angular momentum of a point mass respect the center of the turntable (the person)

\overrightarrow{L_{turnatble}}+\overrightarrow{L_{person}}=constant (1)

The angular momentum of the turntable is:

\overrightarrow{L_{turnatble}}=I\overrightarrow{\omega} (2)

with I the moment of inertia and ω the angular velocity.

The angular momentum of the person respects the center of the turntable is:

\overrightarrow{L_{person}}=\overrightarrow{r}\times m\overrightarrow{v} (3)

with r the position of the person respects the center of the turntable, m the mass of the person and v the linear velocity

Using the fact v=\omega r:

\overrightarrow{L_{person}}=\overrightarrow{r}\times rm\overrightarrow{\omega}(3)

By (3) and (2) on (1) and working only the magnitudes (it's all that we need for this problem):

I\omega+r^{2}m\omega=constant

\omega(I+r^{2}m)=constant

Because the equality should be maintained, if we increase the distance between the person and the center of the turntable (r), the angular velocity should decrease to maintain the same constant value because I and m are constants, so the RPM's (unit of angular velocity) are going to decrease.

4 0
4 years ago
A train travels at a speed of 30 m/s. The train starts at an initial position of 1000 meters and travels for 30 seconds. What is
torisob [31]

Answer:

1900 metres

Explanation:

Given that a train travels at a speed of 30 m/s. The train starts at an initial position of 1000 meters and travels for 30 seconds.

The parameters to be considered are:

Speed = 30 m/s

Time = 30 seconds

Speed = distance/time

Substitute the parameters into the formula

30 = distance / 30

Cross multiply

Distance = 30 × 30

Distance = 900 m

Since the train started from a position of 1000 m , the final position will be:

Final position = 1000 + 900

Final position = 1900 metres

6 0
4 years ago
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