The gravitational force the sun experiences from the earth is 3.48×10²²N, which is exactly the same as the force the sun experiences from the earth.
- Gravity is a force that develops as a result of the attraction between mass-containing objects. The mass of the object has a direct relationship to the strength of this attraction. r equals the separation of two objects.
F = G (M₁M₂)/r²
Where, F the gravitational force
G=6.67×10⁻¹¹Nm²kg⁻² gravitational constant
M₁=5.98×10²⁴kg mass of earth
M₂= 1.99×10³⁰ kg the mass of the sun
r =15×10¹⁰ m is the distance between sun and earth
Putting all the values in above equation,
F = 6.67×10⁻¹¹Nm²kg⁻²(5.98×10²⁴kg 1.99×10³⁰ kg)/15×10¹⁰ m
On solving the above equation we get,
F = 3.48×10²²N
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Answer:
The distance from the radio station is 0.28 light years away.
Solution:
As per the question:
Distance, d = 4 ly
Frequency of the radio station, f = 854 kHz = 
Power, P = 50 kW = 
Now,
From the relation:
P = nhf
where
n = no. of photons/second
h = Planck's constant
f = frequency
Now,
Area of the sphere, A = 
Now,
Suppose the distance from the radio station be 'r' from where the intensity of the photon is 
Now,
We know that:
1 ly = 
Thus
Answer:
The magnitude is 63 kg m²/s, and the direction is -k.
Explanation:
Plug the values into the equation:
L = m v×r
L = (3.0 kg) (<5 i + 3j> m/s × <2i − 3j> m)
Take the cross product. The cross product of two dimensional vectors is:
<v₁ i + v₂ j> × <r₁ i + r₂ j> = <(v₁ r₂ − v₂ r₁) k>
Therefore:
L = (3.0 kg) <((5)(-3) − (3)(2)) k m²/s>
L = (3.0 kg) <-21 k m²/s>
Multiply:
L = <-63 k kg m²/s>
The magnitude is 63 kg m²/s, and the direction is -k.
Answer:
I haven't learnt physics at all yet but I'll try.
After the two cars collide, they move at 6 m/s.
This tells us that the 2nd car which collided with the first car which is 2000 kg is much heavier than the 1st one, if the second one was lighter, the two cars coupled together speed would be much more than just 6 m/s.
Refer to explanation for working.
Explanation:
Now find out how much g or kg is the 2nd car more than the 1st.
2000 ÷ 10 = 200 (I don't really know how to explain this part)
10 - 6 = 4 (Difference for 1st car average speed per second and the coupled cars average speed per second)
200 x 4 = 800
2000 + 800 = 2800 kg
(Final answer)
