Explanation:
ans b hcl and ccl4
both these compounds are formed by sharing of electrons......
Answer:
0.053moles
Explanation:
Hello,
To calculate the number of moles of gas remaining in his after he exhale, we'll have to use Avogadro's law which states that the volume of a given mass of gas is directly proportional to its number of moles provided that temperature and pressure are kept constant. Mathematically,
V = kN, k = V / N
V1 / N1 = V2 / N2= V3 / N3 = Vx / Nx
V1 = 1.7L
N1 = 0.070mol
V2 = 1.3L
N2 = ?
From the above equation,
V1 / N1 = V2 / N2
Make N2 the subject of formula
N2 = (N1 × V2) / V1
N2 = (0.07 × 1.3) / 1.7
N2 = 0.053mol
The number of moles of gas in his lungs when he exhale is 0.053 moles
Answer:
The answer to your question is Only A and B
Explanation:
Reactions
A. 3 AgBr + GaPO₄ → Ag₃PO₄ + GaBr₃
Reactants Elements Products
3 Ag 3
3 Br 3
1 Ga 1
1 P 1
4 O 4
B. 3H₂SO₄ + 2B(OH)₃ → B₂(SO₄)₃ + 6H₂O
Reactants Elements Products
3 S 3
2 B 2
12 H 12
18 O 18
C. Fe + 2 AgNO₃ → Fe(NO₃)₂ + 2 Ag
Reactants Elements Products
1 Fe 1
2 Ag 2
2 N 2
6 O 6
D. C₂H₄O₂ + 2O₂ → 2CO₂ + 2H₂O
Reactants Elements Products
2 C 2
4 H 4
6 O 6
