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dexar [7]
4 years ago
5

Chlorination of ethane yields, in addition to ethyl chloride, a mixture of two isomeric dichlorides. what are the structures of

these two chlorides

Chemistry
1 answer:
jeyben [28]4 years ago
5 0
CH_3 CH_2 Cl has two different types of hydrogen. On further chlorination they are being substituted by chlorine to give two isomeric dichlorides

The structures of the two chlorides are shown below.

Where Hb is replaced by Cl and Ha is replaced by Cl

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Triangle ABC is reflected over the x-axis when is the coordinate for C?
Assoli18 [71]
(1,2 because c is already on the other side so you have to reverse it
4 0
3 years ago
A 250 ml solution of 2.0 M NaOH is diluted to 1.0 liter. What is the final concentration of the solution?
Alex73 [517]

Answer:

Diluted concentration is 0.5M

Explanation:

Let's solve this with rules of three, although there is a formula to see it easier

In 1000 mL (1L), we have 2 moles of NaOH

In 250 mL we must have (250 . 2) / 1000 = 0.5 moles of NaOH

These moles will be also in 1 L of the final volume of the diluted solution

More easy:

1 L of solution has 0.5 moles of NaOH

Then, molarity is 0.5 M

The formula is: Concentrated M . Conc. volume = Diluted M . Diluted volume

2 M . 0.250L = 1L . Diluted M

0.5M = Diluted M

3 0
4 years ago
Read 2 more answers
How many moles of CO are produced when 1.8 moles C reacts?
olasank [31]

Answer:

1.44mole of CO

Explanation:

The reaction equation is given as:

         5C  + 2SO₂ →  CS₂ + 4CO

We check to see if the expression is balanced and it is so;

 Now;

 Given;

           1.8mole of C reacted; how many moles of CO are produced;

  From the balanced reaction equation:

             5 mole of C is expected to produce 4 mole of CO

             1.8 mole of C will then produce \frac{4  x 1.8}{5} = 1.44mole of CO

3 0
3 years ago
Butane C4H10 (g),(Hf = –125.7), combusts in the presence of oxygen to form CO2 (g) (Delta.Hf = –393.5 kJ/mol), and H2O(g) (Delta
shusha [124]

Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ

Explanation:

The balanced chemical reaction is,

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

The expression for enthalpy change is,

\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]

Putting the values we get :

\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]

\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]

\Delta H=-5314.8kJ

2 moles of butane releases heat = 5314.8 kJ

1 mole of butane release heat = \frac{5314.8}{2}\times 1=2657.4kJ

Thus enthalpy of combustion per mole of butane is -2657.4 kJ

3 0
3 years ago
A scientist conducts experiments to test what temperature causes the fastest growth rate in sunflower plantsafter multiple trial
Svetllana [295]

Answer:

Repetition

Explanation:

In the world of science, experiments are regularly conducted to test out hypotheses. These experiments are however, not conducted by scientist once to derive a result. They are rather conducted multiple times (repeated) to ascertain the accuracy i.e not as a result of random occurrence. The experiments that undergo multiple trials are said to undergo REPETITION.

This is the case of the scientist in this question, who is conducting an experiment to test what temperature causes the fastest growth rate in sunflower plants. He conducted the experiment multiple times, making it an example of REPETITION.

N.B: Replication is when the experiment is re-conducted by another scientist to see if same result is derived.

8 0
3 years ago
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