A large volume of material will have a small amount of mass when the
material in question is gaseous or porous, and therefore has a lot of
space within it despite taking up a large amount of space overall.
The empirical formula is XeO₃.
<u>Explanation:</u>
Assume 100 g of the compound is present. This changes the percents to grams:
Given mass in g:
Xenon = 73.23 g
Oxygen = 26.77 g
We have to convert it to moles.
Xe = 73.23/
131.293 = 0.56 moles
O = 26.77/ 16 = 1.67 moles
Divide by the lowest value, seeking the smallest whole-number ratio:
Xe = 0.56/ 0.56 = 1
O = 1.67/ 0.56 = 2.9 ≈3
So the empirical formula is XeO₃.
The most likely formula for an oxide formed between group 1a atom X and oxygen would be
X2O. - X is group 1a atom.
578.23 miles = 930.6 kilometers (Rounded up to the nearest tenth.)
