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UNO [17]
3 years ago
6

(-4+2i)(7-2i) Anyone know how to do this??

Mathematics
1 answer:
avanturin [10]3 years ago
4 0

Answer:

<h2>-24 + 22i</h2>

Step-by-step explanation:

Use the FOIL method of multiplication of binomials:

(-4+2i)(7-2i) = -28 + 14i + 8i - (-4)i²

Note that i² = -1.  Thus, - (-4)i² = +4, and we then have:

-28 + 22i + 4, or

-24 + 22i

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The graph of a proportional relationship passes through the point (6, 21). What is the equation for the relationship?​
Kipish [7]

Answer:

The equation for the relationship is y = \frac{7}{2}\cdot x.

Step-by-step explanation:

Given that point (x,y) = (6, 21) is part of a direct relationship. That is:

y \propto x

y = k\cdot x (1)

Where k is the proportionality constant.

If we know that x = 6 and y = 21, then the proportionality constant is:

k = \frac{y}{x}

k = \frac{21}{6}

k = \frac{7}{2}

Lastly, the equation for the relationship is y = \frac{7}{2}\cdot x.

7 0
3 years ago
What is 2 + 2????????????????????
Bogdan [553]
4 would be your answer lol
3 0
2 years ago
Read 2 more answers
Can someone show me the answer + how they got there? (x+4)(x-1)
Naily [24]

Answer:

x^2+3x-4

Step-by-step explanation:

x * x - x + 4x - 4

x^2 - x + 4x - 4

x^2 + 3x - 4

6 0
3 years ago
Read 2 more answers
If f(x)=4x^2+1 and g(x)=x^2-5 find(f+g)(x)
Zepler [3.9K]

Answer:

\large\boxed{(f+g)(x)=5x^2+6}

Step-by-step explanation:

(f+g)(x)=f(x)+g(x)\\\\f(x)=4x^2+1,\ g(x)=x^2-5\\\\\text{Substitute:}\\\\(f+g)(x)=(4x^2+1)+(x^2-5)\\\\=4x^2+1+x^2-5\qquad\text{combine like terms}\\\\=(4x^2+x^2)+(1+5)\\\\=5x^2+6

6 0
3 years ago
Find the value of x.<br> 76
azamat
This picture is depicting a straight line, therefore all we have to do is subtract 76 from 180. You get 104

Your answer is 104 degree
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3 years ago
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