Ask question

Ask question

All categories

Thepotemich [5.8K]

3 years ago

15

What is the growth factor of the following example? Assume time is measured in the units given. Water usage is increasing by 3%

per year.

1 answer:

sammy [17]3 years ago

3 0

<span>At a 3% increase you would use 1.03 * 1000 L = 1030 L next year</span>

You might be interested in

What is the answer to this? −1.3≥2.9−0.6r

Karolina [17]

Answer:

Inequality Form:

r ≥ 7

Interval Notation:

[7, ∞)

Step-by-step explanation:

−1.3 ≥ 2.9 − 0.6r

Rewrite so r is on the left side of the inequality.

2.9 − 0.6r ≤ −1.3

Move all terms not containing r to the right side of the inequality.

Subtract 2.9 from both sides of the inequality.

−0.6r ≤ −1.3 − 2.9

Subtract 2.9 from −1.3.

−0.6r ≤ −4.2

Divide each term by −0.6 and simplify.

Divide each term in −0.6r ≤ −4.2 by −0.6. When multiplying or dividing both sides of an

inequality by a negative value, f lip the direction of the inequality sign.

−0.6r /−0.6 ≥ −4.2 /−0.6

Cancel the common factor of −0.6.

−4.2

r ≥ ______

−0.6

Divide −4.2 by −0.6.

r ≥ 7

The result can be shown in multiple forms.

Inequality Form:

r ≥ 7

Interval Notation:

[7, ∞)

6 0

3 years ago

Select the objects that hold the same amount of liquid as 160 fluid ounce jug spect all that apply A four 8 ounce fluid glasses

Olegator [25]

The answer is D .....

7 0

3 years ago

The letters of the word ATLANTIC are put in a bag. What is the probability of

gladu [14]

Answer:

5/8

Step-by-step explanation:

A T L A N T I C

8 letters, 3 vowels, 5 consonants

5 consonants out of 8 letters = 5/8

7 0

3 years ago

Read 2 more answers

in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)

Nimfa-mama [501]

Answer:

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

Step-by-step explanation:

Let $\vec u$ and $\vec a$ , from Linear Algebra we get that component of $\vec u$ parallel to $\vec a$ by using this formula:

$\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a$ (Eq. 1)

Where $\|\vec a\|$ is the norm of $\vec a$ , which is equal to $\|\vec a\| = \sqrt{\vec a\bullet \vec a}$ . (Eq. 2)

If we know that $\vec u =(2,1,1,2)$ and $\vec a=(4,-4,2,-2)$ , then we get that vector component of $\vec u$ parallel to $\vec a$ is:

$\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

Lastly, we find the vector component of $\vec u$ orthogonal to $\vec a$ by applying this vector sum identity:

$\vec u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a}$ (Eq. 3)

If we get that $\vec u =(2,1,1,2)$ and $\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$ , the vector component of $\vec u$ is:

$\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

$\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

4 0

3 years ago

Each one of four pies were cut into 8 pieces for dinner. After dinner there remained 1/2 of a pie, o pie, 3/8 of a pie and 5/$of

Marizza181 [45]

Answer: What you would have left is 12 pieces of pie

Step-by-step explanation: As stated in the question, one pie has been sliced into 8 pieces, and there are three pies in all. That means we had at the beginning 3 x 8 slices of pie which equals 24 pieces.

Also if each pie had been sliced into 8 pieces then each can be represented as 8/8. Therefore eating one slice would leave you with 7/8 (that is 8/8 minus 1/8).

So, each of the three pies now have the following left overs;

1/2, 3/8 and 5/8.

Adding them all together would give,

1/2 + 3/8 + 5/8

Using 8 as the common denominator

4/8 + 3/8 + 5/8

(4 + 3 + 5)/8

12/8.

Therefore, there would be 12 pieces left altogether, which can also be expressed as one pie and 4 pieces.

8 0

3 years ago