Hydrogen and Helium cannot bond together. Put aside the inertness of helium (or all noble gases), bond formation is only favored when the final state of the two elements is more stable than their initial state. ... Helium compounds has some predictions though none of them contain only those two elements.
1) The forward reaction is N2 (g) + O2 (g) → 2NO
(that reaction requires special contitions because at normal pressures and temperatures N2 and O2 do not react to form another compound.
2) The equiblibrium equation is
N2 (g) + O2 (g) ⇄ 2NO
3) Then, the reverse reaction is
2NO → N2(g) + O2(g)
Answer: 2NO → N2(g) + O2(g)
Yea it's c it's a living component
Answer : the hydrogen ion concentrations for pH = 7.35 and pH = 7.45 are 4.46 x 10⁻⁸ M and 3.54 x 10⁻⁸ M respectively.
When the pH of a solution is less than 7, the hydrogen ion concentration is higher and therefore the solution is acidic.
On the other hand, when the pH of a solution is greater than 7, hydroxide ion concentration is higher and the solution acts as a base.
The normal pH range of blood is given as 7.35 - 7.45 which is greater than 7. That means blood is slight basic in nature.
Let us find hydroxide ion concentration of blood.



![pOH = - log [OH-]](https://tex.z-dn.net/?f=pOH%20%3D%20-%20log%20%5BOH-%5D)
![[OH-] = 10^{-6.65}](https://tex.z-dn.net/?f=%5BOH-%5D%20%3D%2010%5E%7B-6.65%7D)
![[OH-] = 2.24 \times 10^{-7}](https://tex.z-dn.net/?f=%5BOH-%5D%20%3D%202.24%20%5Ctimes%2010%5E%7B-7%7D)
Ionic product of water is written as,
![[H+] [OH-] = 1 \times 10^{-14}](https://tex.z-dn.net/?f=%5BH%2B%5D%20%5BOH-%5D%20%3D%201%20%5Ctimes%2010%5E%7B-14%7D)
Let us plug in the calculated value of [OH-]
![[H+] = \frac{1 \times 10^{-14}}{2.24 \times 10^-7} = 4.46 \times 10^{-8} M](https://tex.z-dn.net/?f=%5BH%2B%5D%20%3D%20%5Cfrac%7B1%20%5Ctimes%2010%5E%7B-14%7D%7D%7B2.24%20%5Ctimes%2010%5E-7%7D%20%3D%204.46%20%5Ctimes%2010%5E%7B-8%7D%20M)
The hydrogen ion concentration for pH = 7.35 is 4.46 x 10⁻⁸ M
Calculation of [H+] for pH = 7.45
pOH = 6.55
[OH-] = 2.82 x 10⁻⁷
![[H+] = \frac{1 \times 10^{-14}}{2.82 \times 10^-7} = 3.54 \times 10^{-8} M](https://tex.z-dn.net/?f=%5BH%2B%5D%20%3D%20%5Cfrac%7B1%20%5Ctimes%2010%5E%7B-14%7D%7D%7B2.82%20%5Ctimes%2010%5E-7%7D%20%3D%203.54%20%5Ctimes%2010%5E%7B-8%7D%20M)
Similarly, for pH = 7.45, we get hydrogen ion concentration of 3.54 x 10⁻⁸ M.
<span> that the reaction is preferably called an elimination, rather than a dehydration, although I personally like the term dehydration because it emphasizes the strong dehydrating power of H2SO4 that is unfotunately forgotten too often by undergraduates. I like to think of it as H2SO4 has such a strong affinity for water that it literally pulls water molecules from organics.</span>