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4 years ago

If an aquatic animal relies on photosynthesis to survive, in which ocean zone would it be most successful?

Chemistry

2 answers:

Leya [2.2K]4 years ago

3 0

It is the epipelagic zone.

Nadusha1986 [10]4 years ago

3 0

Epipelagic Zone is the answer!!

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Calculate the wavelength of a photon of light having a frequency of 3.50 x 1015 Hz.

Aliun [14]

Answer:

Wavelength, $\lambda=8.57\times 10^{-8}\ m$

Explanation:

Given that,

Frequency, $f=3.5\times 10^{15}\ Hz$

We need to find the wavelength of a photon of light. The relation between frequency and wavelength is as follows :

$c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{3.5\times 10^{15}}\\\\\lambda=8.57\times 10^{-8}\ m$

So, the wavelength of the light is $8.57\times 10^{-8}\ m$ .

4 0

3 years ago

A chemistry instructor provides each student with 8 test tubes at the beginning of the year. If there are 28 students per class,

Ann [662]

Answer :8*28=224
224*3=672

7 0

4 years ago

At a particular temperature a 2.00-L flask at equilibrium contains 2.80 ✕ 10-4 mol N2, 2.50 ✕ 10-5 mol O2, and 2.00 ✕ 10-2 mol N

zhenek [66]

Answer : The value of equilibrium constant (K) is, $5.71\times 10^4$

Explanation :

First we have to calculate the concentration of $N_2,O_2\text{ and }N_2O$

$\text{Concentration of }N_2=\frac{\text{Moles of }N_2}{\text{Volume of solution}}=\frac{2.80\times 10^{-4}mol}{2.00L}=1.4\times 10^{-4}M$

and,

$\text{Concentration of }O_2=\frac{\text{Moles of }O_2}{\text{Volume of solution}}=\frac{2.50\times 10^{-5}mol}{2.00L}=1.25\times 10^{-5}M$

and,

$\text{Concentration of }N_2O=\frac{\text{Moles of }N_2O}{\text{Volume of solution}}=\frac{2.00\times 10^{-2}mol}{2.00L}=1.00\times 10^{-2}M$

Now we have to calculate the value of equilibrium constant (K).

The given chemical reaction is:

$N_2(g)+O_2(g)\rightarrow 2N_2O(g)$

The expression for equilibrium constant is:

$K=\frac{[N_2O]^2}{[N_2][O_2]}$

Now put all the given values in this expression, we get:

$K=\frac{(1.00\times 10^{-2})^2}{(1.4\times 10^{-4})\times (1.25\times 10^{-5})}$

$K=5.71\times 10^4$

Thus, the value of equilibrium constant (K) is, $5.71\times 10^4$

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4 years ago

Which properties change the composition of a substance? A physical properties

Ugo [173]

The correct answer is B.

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3 years ago

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Drupady [299]

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3 years ago

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