X squared divided 2=w-y make x the subject

How do you integrate <br><img src="https://tex.z-dn.net/?f=%283x%5E%7B2%7D%20%20%2B%203%29%20%5E%7B3%7D%20" id="TexFormula1" tit

Phoenix [80]

Answer:

Since i don't know what formula is mentioned. I just used the easiest way to solve :)

Step-by-step explanation:

$(3x^2 + 3)^3 = (3x^2)^3 + 3^3 + 3((3x^2)^2)(3) + 3(3x^2)(3^2)$

$= 27x^6 + 27 + 3(9x^4 \times 3) + 3(3x^2 \times 9)\\\\=27x^6 + 27 + 81x^4 + 81x^2\\\\=27x^6 + 81x^4 + 81x^2 + 27\\\\$

$\int\limits {(3x^2+3)^3} \, dx = \int\limits {27x^6 + 81x^4+81x^2 + 27} \, dx$

$= \frac{27}{7}x^7 + \frac{81}{5}x^5+\frac{81}{3}x^3 + 27x +C\\\\= \frac{27}{7}x^7 + \frac{81}{5}x^5+27x^3 + 27x +C\\\\$

8 0

2 years ago

Theo had a balance of -4 in his savings account. After making a deposit , he has $25 in his account . What is the overall change

ozzi

Theos initial balance in his savings account = -$4
Final balance after making a deposit = $25
So, the overall change to his account = $ 29

6 0

2 years ago

WILL GIVE BRAINLIEST

tiny-mole [99]

The expressions for each of the given statements are

a. 6 + z

b. 20 - x

c. x/6 - 8

d. x + 5/4

<h3>Writing an expression </h3>

From the question, we are to write an expression for each of the given statement

a. the sum of 6 and z

That is,

6 + z

b. the difference between 20 and x

That is,

20 - x

c. 8 less than the quotient of x divided by 6

That is,

x/6 - 8

d. x increased by 5 divided by 4

That is,

x + 5/4

Hence, the expressions for each of the given statements are

a. 6 + z

b. 20 - x

c. x/6 - 8

d. x + 5/4

Learn more on Writing an expression here: brainly.com/question/17651563

#SPJ1

4 0

1 year ago

What is 6 3/5 - 4 3/5

jekas [21]

You do 3/5 minus 3/5 which cancels out to 0. Then you do 6 minus 4 which is 2. The answer is 2.

6 0

3 years ago

Read 2 more answers

The function f(x) = 4(4)x represents the growth of a fly population every year in a remote swamp. Jackie wants to manipulate the

Sauron [17]

The function f(x) = 4(4)x represents the growth of a fly population every year in a remote swamp.

calculates three times a year, not just once a year.

$f(x)= 4(4)^x$

3 times a year

so x becomes 3x

$f(x)= 4(1+r)^{3x}$

$4(4)^x=4(1+r)^{3x}$

Take log on both sides

$log(4)^x=log(1+r)^{3x}$

Use log property and move exponent before log

$xlog(4)=3xlog(1+r)}$

Divide both sides by x

log 4 = 3 log(1+r)

Solve for '1+r'

log 4 = log(1+r)^3

Remove log from both sides

4 = (1+r)^3

take cube root on both sides

1.584740= 1+r

1+r = 1.59

$f(x)= 4(1+r)^{3x}$

so equation becomes

$f(x)= 4(1.59)^{3x}$

1+r = 1.59

subtract 1 from both sides

So r= 59 = 59%

So growth factor is 59%

Answer is option C

5 0

2 years ago