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alekssr [168]
4 years ago
8

An astronomer observes a hydrogen line in the spectrum of a star. The wavelength of hydrogen in the laboratory is 6.563 x 10-7m,

but the wavelength in the star's light is measured at 6.56186 x 10-7m. Which of the following explains this discrepancy? A.The star is moving away from Earth B. The wavelength of light that the star is emitting changes constantly. C.The frequency of light that the star is emitting changes constantly. D. The star is approaching Earth.
Physics
1 answer:
Sergio [31]4 years ago
8 0

Answer:

D. The star is approaching Earth.

Explanation:

As we know by the doppler's effect of light that

\frac{\Delta \nu}{\nu} = \frac{v}{c}

here we know that

\Delta \nu = change in frequency

here we know that the wavelength of light coming from the star is decreased so the frequency will increase

\Delta \nu = \frac{c}{\lambda'} - \frac{c}{\lambda}

\Delta \nu =(3\times 10^8)(\frac{1}{6.56186 \times 10^{-7}} - \frac{1}{6.563 \times 10^{-7}})

\Delta \nu = 7.9414 \times 10^{10} Hz

now we have

\frac{7.9414 \times 10^{10}}{\nu} = \frac{v}{c}

here we know that

\nu = \frac{3\times 10^8}{6.563 \times 10^{-7}} = 4.57 \times 10^{14} Hz

now we have

v = 5.2 \times 10^4 m/s

So here correct answer is

D. The star is approaching Earth.

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A 1-lb block and a 100-lb block are placed side by side at the top of a frictionless hill. Each is given a very light tap to beg
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You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between
Murljashka [212]

Answer:

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Explanation:

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b) In this case the ball bounces with a speed of V₂ = -7.80 m / s, the negative sign is because it is going in opposite directions

let's write the moment in two times

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try end. Right after the crash

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the moment is preserved

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       v = 0.405 /69   (8.50 - (7.80))

       v = 0.0957 m / s

in the initial direction of the ball

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