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romanna [79]
3 years ago
5

Why doe cups break in the winter?

Physics
2 answers:
Viktor [21]3 years ago
8 0

Usually,  when pour water into a glass, the more thick glass is easier to break. Because the glass tumbler is cold, when hot water is poured, and the inner wall expands rapidly due to thermal expansion and contraction.  

eimsori [14]3 years ago
5 0

Answer: Glass may break at low temperatures, but this is because the contents freeze and their expansion cause the glass to crack (if the cap does not come off). ... Hot temperatures can cause the glass to break when the bottle is subject to excessive thermal variations. hope this helps can u give me brainliest

Explanation:

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A soccer player is running upfeild at 10m/s and comes to a stop in 3 seconds facing in the same direction what is his accelerati
kumpel [21]
-3.33 m/s^2



The soccer player decelerates from 10 m/s to 0 m/s. Because he decelerates the acceleration will be a negative value. Since he takes 3 seconds to decelerate, divide his original velocity by 3



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4 years ago
A coin is dropped from a height and reaches the ground in 2 seconds. Neglecting air resistance, from what height (in meters) was
Kamila [148]

Answer:

Coin is dropped from a height of 19.62 m

Explanation:

We have given time t = 2 sec

As coin is drop means its initial velocity u = 0 m/sec

We have to find the height from which coin is dropped

From second equation of motion we know that

h=ut+\frac{1}{2}gt^2

So height h=0\times2+\frac{1}{2}\times 9.81\times 2^2=19.62m

So coin is dropped from a height of 19.62 m

3 0
3 years ago
What is the displacement if I walk three blocks east two blocks south one block west and two blocks north
vladimir1956 [14]

Answer:

south east

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4 0
3 years ago
Important result of french revolution
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The french revolution led to many deaths and impacted history because of the amount of life lost
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three girls were pushing the same car with a net force of 450 N [N48°E]. Two of the girls were pushing with forces of 310 N [N25
ElenaW [278]

The net force is the vector

∑ F = (450 N) (cos(42°) i + sin(42°) j)

and two of the forces provided by the girls are

F₁ = (310 N) (cos(115°) i + sin(115°) j)

F₂ = (250 N) (cos(285°) i + sin(285°) j)

Then the force provided by the third girl is the vector

F₃ = ∑ F - F₁ - F₂

F₃ = ((450 N) cos(42°) - (310 N) cos(115°) - (250 N) cos(285°)) i

… … … + ((450 N) sin(42°) - (310 N) sin(115°) - (250 N) sin(285°)) j

F₃ ≈ (400.722 N) i + (261.635 N) j

So, the third girl provided a force of magnitude

||F₃|| = √((400.722 N)² + (261.635 N)²) ≈ 478.572 N ≈ 480 N

pointing in a direction

arctan((261.635 N)/(400.722 N)) ≈ 33.1409° ≈ 33°

relative to East which refers to 0°; that is, 33° N of E or E33°N. Since the other forces are given relative to North or South, we can write this direction as N57°E.

So, the third girl pushed with force 480 N [N57°E].

5 0
3 years ago
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