Refer to the diagram shown below.
The component of the applied force perpendicular to the door is
F * sin(60°) = 0.866F N
Because the moment arm is 0.40 m, the torque is
(0.866F N)*(0.4 m) = 0.3464F N-m
This torque is equal to 1.4 N-m, therefore
0.3464F = 1.4
F = 4.04 N
Answer: 4.04 N
Answer:
B hopefully this helps you with work
1. The speed in kilometers per hour (Km/h) is 133.2 Km/h
2. Yes, the speed is exceeding the 125 Km/h limit
<h3>How to convert 37 m/s to Km/h</h3>
From the question given above, the following data were obtained:
- Speed (in m/s) = 37 m/s
- Speed (in Km/h) =?
We can convert 37 m/s to kilometers per hour (Km/h) by doing the following:
1 m/s = 3.6 Km/h
Therefore,
37 m/s = 37 × 3.6
37 m/s = 133.2 Km/h
Thus, 37 m/s is equivalent to 133.2 Km/h
<h3>2. How to determine if the speed is exceeding the limit</h3>
- Speed of car = 133.2 Km/h
- Speed limit = 125 Km/h
From the above, we can see that the speed of the car is greater than the speed limit.
Thus, we can conclude that the speed of the car is exceeding the speed limit.
Learn more about conversion:
brainly.com/question/10893215
#SPJ1
Answer:
A car weighing 15 grams
Explanation:
According to the equation that shows the relationship between mass (m), force (F), and acceleration (a) i.e. F = ma, it can be seen that with a constant force, the mass is inversely proportional to the acceleration.
This means that an increase in mass of an object denotes a decrease in acceleration of that object and vice versa. Hence, according to this question, when pushed with the same amount of force, a car with the least mass will move faster. This car is the car weighing 15grams.
