No, no me habla espanol. yo soy ingles
Answer:
W = 289.70 kg
Explanation:
Given data:
Pressure in tank = 23 atm
Altitude 1000 ft
Air temperature in tank T = 700 F
Volume of tank = 800 ft^3 = 22.654 m^3
from ideal gas equation we have
PV =n RT
Therefore number of mole inside the tank is
we know that 1 mole of air weight is 28.97 g
therefore, tank air weight is 
W = 289.70 kg
Answer:
Private Investigator.
Investigative Genetic Genealogist.
Historic Preservationist.
Military Repatriation Expert.
Heir Searcher.
Explanation:
To solve the problem it is necessary to refer to the definition of entropy.
Entropy is defined aso
Where,
Heat exchange
T = Temperature
Since the heat exchange is conserved and it is an isothermal process where the temperature remains constant the change in entropy remains the same, ie 
(Reamins same)
Therefore the correct answer is C.
Apparently, the question is looking for A. electric potential energy;
but I don't think that's quite right. Electric potential difference is expressed in Joules / Coulomb which is the work to move a charge between 2 points
Example: If the electric field between, say, between 2 capacitor plates is
E = 100 Newtons / Coulomb then the work done in moving a unit of charge from the negative plate to the positive plate separted by 1 cm is
V = E * d = 100 Newtons / Coulomb * .01 meters = 1 Newton-meter / Coulomb
= 1 Joule / Coulomb which is the electric potential or potential difference
(The definition of electric potential between points is "the work moving a unit positive test charge from one point to the other")
Now in our above example where V = 1 Joule / Coulomb
if we move 10 Coulombs from the negative plate to the positive plate
W = V Q = 1 Joule / Coulomb * 10 Coulombs = 10 Joules
where work done has the correct units of Joules.
Your textbook should help clarify this.
