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romanna [79]
3 years ago
5

Why doe cups break in the winter?

Physics
2 answers:
Viktor [21]3 years ago
8 0

Usually,  when pour water into a glass, the more thick glass is easier to break. Because the glass tumbler is cold, when hot water is poured, and the inner wall expands rapidly due to thermal expansion and contraction.  

eimsori [14]3 years ago
5 0

Answer: Glass may break at low temperatures, but this is because the contents freeze and their expansion cause the glass to crack (if the cap does not come off). ... Hot temperatures can cause the glass to break when the bottle is subject to excessive thermal variations. hope this helps can u give me brainliest

Explanation:

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Si uno de los valores de la tabla no se visualiza en el gráfico, ¿Cómo lo encontramos?
ivanzaharov [21]
No, no me habla espanol. yo soy ingles
6 0
2 years ago
If the atmospheric pressure in a tank is 23 atmospheres at an altitude of 1,000 feet, the air temperature in the tank is 700F, a
liraira [26]

Answer:

W = 289.70 kg

Explanation:

Given data:

Pressure in tank = 23 atm

Altitude 1000 ft

Air temperature  in tank T = 700 F

Volume of tank = 800 ft^3 = 22.654 m^3

from ideal gas equation we have

PV =n RT

Therefore number of mole inside the tank is

\frac{1}{n} = \frac{RT}{PV}

              = \frac{8.206\times 10^{-5}} 644.261}{23\times 22.654}

               = 1.02\times 10^{-4}

               n = 10^4 mole

we know that 1 mole of air weight is 28.97 g

therefore, tank air weight is W = 10^4\times 28.91 g = 289700 g

               W = 289.70 kg

6 0
2 years ago
Create a list of 5 potential jobs that students of genealogy can obtain.
Kipish [7]

Answer:

Private Investigator.

Investigative Genetic Genealogist.

Historic Preservationist.

Military Repatriation Expert.

Heir Searcher.

Explanation:

4 0
2 years ago
Question 2 An ideal gas in a piston/cylinder device is compressed at constant temperature. The entropy of the ideal gas will:
Flura [38]

To solve the problem it is necessary to refer to the definition of entropy.

Entropy is defined aso

\Delta S = \frac{\Delta Q}{T}

Where,

\Delta Q = Heat exchange

T = Temperature

Since the heat exchange is conserved and it is an isothermal process where the temperature remains constant the change in entropy remains the same, ie \Delta S = 0 (Reamins same)

Therefore the correct answer is C.

8 0
3 years ago
While solving a problem, Tran calculates an answer that has coulomb-volts as the units.
Bess [88]

Apparently, the question is looking for A. electric potential energy;

but I don't think that's quite right. Electric potential difference is expressed in Joules / Coulomb which is the work to move a charge between 2 points

Example: If the electric field between, say, between 2 capacitor plates is

E = 100 Newtons / Coulomb then the work done in moving a unit of charge from the negative plate to the positive plate separted by 1 cm is

V = E * d = 100 Newtons / Coulomb * .01 meters = 1 Newton-meter / Coulomb

= 1 Joule / Coulomb    which is the electric potential or potential difference

(The definition of electric potential between points is "the work moving a unit positive test charge from one point to the other")

Now in our above example where V = 1 Joule / Coulomb

if we move 10 Coulombs from the negative plate to the positive plate

W = V Q  = 1 Joule / Coulomb * 10 Coulombs = 10 Joules

where work done has the correct units of Joules.

Your textbook should help clarify this.

4 0
3 years ago
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