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3 years ago

Why doe cups break in the winter?

2 answers:

8 0

Usually, when pour water into a glass, the more thick glass is easier to break. Because the glass tumbler is cold, when hot water is poured, and the inner wall expands rapidly due to thermal expansion and contraction.

eimsori [14]3 years ago

5 0

Answer: Glass may break at low temperatures, but this is because the contents freeze and their expansion cause the glass to crack (if the cap does not come off). ... Hot temperatures can cause the glass to break when the bottle is subject to excessive thermal variations. hope this helps can u give me brainliest

Explanation:

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Suppose that on a hot (33.0°C) and sticky (80% humidity) afternoon in the spring, a tornado passes over the high school. If the

pickupchik [31]

Answer:

V₂ = 225 m^{3}

so no exact option is match with the calculated answer.

Explanation:

According to Boyle's Law, we have

P_1 V_1 = P_2 V_2 ----------- (1)

Data Given;

P_1 = 1.0 atm

V_1 = 180 m³

P_2 = 0.80 atm

V_2 = ?

Solving equation 1 for V₂,

$V_2= \frac{P_1 V_1}{P_1}$

Putting values,

$V_2 = \frac{1.0*180}{0.80}$

$V_2 = 225 m^{3}$

so no exact option is match with the calculated answer.

6 0

3 years ago

Read 2 more answers

A particle of unit mass moves in a potential V(x)= ax^2+b/x^2 . Where a and b are constnts. Calcuate the angular frequency of sm

Sholpan [36]

Answer:

Explanation:

Given

Potential Energy is given by

$U(x)=ax^2+\frac{b}{x^2}$

And Force is given by

$F=-\frac{\mathrm{d} U}{\mathrm{d} x}$

Particle will be at equilibrium when Potential Energy is either minimum or maximum

$F=-\left ( 2ax-\frac{2b}{x^3}\right )$

i.e. $ax=\frac{b}{x^3}$

$x_0=(\frac{b}{a})^{0.25}$

So angular Frequency of small oscillation is given by

$\omega =\sqrt{\frac{U''(x)}{m}}$

for $m=1$

we get $\omega =\sqrt{\frac{U''(x_0)}{1}}$

$U''(x_0)=2a+6a= 8a$

$\omega =\sqrt{8a}$

4 0

3 years ago

A jet engine gets its thrust by taking in air, heating and compressing it, and

nadya68 [22]

Answer:

$F=ma=20\ Kg\ 400\ m/s^2=8,000\ Nw$

Explanation:

Thrust is known as a reaction force which appears when a system expels or accelerates mass in one specific direction. If we know the acceleration and the mass of the air expelled by the jet engine, we can compute the thrust .

The acceleration is calculated by using the dynamics formula

$\displaystyle a=\frac{v_f-v_o}{t}$