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Answer:
Area of rectangle is
Perimeter of Rectangle is .
Step-by-step explanation:
Given:
Let the width of the rectangle be 'w'.
Also Given:
A rectangle has a length that is 5 meters greater than the width.
Length of rectangle =
We need to write expression for Area of rectangle and Perimeter of rectangle.
Solution:
Now we know that;
Perimeter of rectangle is equal to twice the sum of the length and width.
framing in equation form we get;
Perimeter of rectangle =
Also We know that;
Area of rectangle is length times width.
framing in equation form we get;
Area of rectangle=
Hence Area of rectangle is and Perimeter of Rectangle is
.
Answer:
(see below)
Step-by-step explanation:
A reflection across the y-axis is the same thing, but just mirrored on the other side. In this case, "the other side" is the y-axis.
The original rectangle was two units away from the y-axis, so this new rectangle needs to be as well.
Its area needs to also be 2 units big.
Pretty much, it's the same thing and you just place it up to a mirror.
Refer to the image below:
Answer:
The answer is below
Step-by-step explanation:
The co-vertices of an ellipse are the endpoints of the minor axis. The equation for an ellipse is given by:
Where (h, k) is the center of the ellipse, (h, k±b) is the co-vertices, (h ± a, k) is the vertices, (h ± c, k) is the foci and c² = a² - b²
Since the center is the origin, hence (h, k) = (0, 0). i.e h = 0, k = 0.
Foci = (h ± c, k) = (± c, 0) = (±3, 0). c = 3
co-vertices = (h, k±b) = (0, ±b) = (0, ±4). b = 4
c² = a² - b²
a² = c² + b²
a² = 3² + 4² = 25
a = 5
Therefore the equation of the ellipse is: