Answer:
D. Two reactants combine to form a single ew product.
Explanation:
Because, A decomposition reaction produces multiple products from a single reactant.
Cofactors:
A. Coenzyme A (CoA-SH)
B. NAD+
C. Thiamine pyrophosphate (TPP)
D. FAD
E. Lipoic acid in oxidized form
Roles:
E... Attacks and attaches to the central carbon in pyruvate.
A...Oxidizes FADH2.
C...Accepts the acetyl group from reduced lipoic acid.
D... Oxidizes the reduced form of lipoic acid.
B... Initial electron acceptor in oxidation of pyruvate.
Answer:
1. Abiotic
2. Biotic
3. Biotic
Explanation:
Abiotic includes nonliving.
Biotic includes living.

<h3>Explanation</h3>
Find the oxidation state for each element.
The oxidation state of H is +1 in most compounds.
- The S atom in H₂S is bonded to two H atoms. The oxidation state of S in H₂S will be -(2 × (+1)) = -2.
- Two O atom in H₂O₂ are bonded to two H atoms. On average, the oxidation state for each O atom in H₂O₂ will be - 1/2 × (2 × (+1)) = -1.
- S has an oxidation state of 0 when it is not bonded to any other element;
- The O atom in H₂O is bonded to two H atoms. The oxidation state of O in H₂O will be -(2 × (+1)) = -2.
Changes in oxidation states:
- S: from -2 to 0.
- O: from -1 to -2.
Each S atom will reduce two O atoms. There are two O atoms in each H₂O₂ molecule. There's only one S atom in each H₂S molecule. As a result, pairing one H₂O₂ with one H₂S will balance the change in oxidation state.
Each H₂O₂ contains two O atoms. The two O atoms will produce two H₂O molecules. Each H₂S molecule will lead to one S molecule. Thus the coefficient for H₂O will be two and the coefficient for the rest three species will be one.
Answer:
Homopolysaccharides are polysaccharides composed of a single type of sugar monomer.