Given the percentage composition of HC as C → 81.82 % and H → 18.18 %
So the ratio of number if atoms of C and H in its molecule can will be:
C : H = 81.82 12 : 18.18 1 C : H = 6.82 : 18.18 = 6.82 6.82 : 18.18 6.82 = 1 : 2.66 ≈ 3 : 8
So the Empirical Formula of hydrocarbon is:
C 3 H 8
As the mass of one litre of hydrocarbon is same as that of C O 2 The molar mass of the HC will be same as that of C O 2 i.e 44 g mol
Now let Molecular formula of the HC be ( C 3 H 8 ) n
Using molar mass of C and H the molar mass of the HC from its molecular formula is:
( 3 × 12 + 8 × 1 ) n = 44 n So 44 n = 44 ⇒ n = 1
Hence the molecular formula of HC is C 3 H 8
Does that help?
Put a thermometer in the water and wait until it boils. When it boils record the temperature and compare it to the normal water boiling point.
First find the RFM (Relative Formula Mass) using a periodic table
the RFM of Ca(OH)2 is = 74
then use the equation Moles = Mass / RFM
Moles = 7.4 / 74 = 0.1mol
<span>hope that helps</span>
Answer:
am can u pliz tell me more about ur qtn
Explanation:
like a nuclear of a what
maybe a plant or and animal
