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Eduardwww [97]
3 years ago
7

What is a male function

Chemistry
1 answer:
vazorg [7]3 years ago
8 0
The purpose of the male function is to transport and maintain sperm
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I need help.connect now
olya-2409 [2.1K]
And the help is.....?!
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3 years ago
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The density of liquid oxygen at its boiling point is 1.14 kg/L , and its heat of vaporization is 213 kJ/kg . How much energy in
-Dominant- [34]
<span>2.28 kg x 213 kJ/kg = 486 kJ = 4.86E+05 J</span>
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3 years ago
Which part of an atom is actively exchanged or shared in a chemical bond?
denpristay [2]

The part of an atom that is actively exchanged or shared in a chemical bond is ELECTRON.

An atom is made up of three sub particles, which are electron, proton and neutron. The proton and the neutron are located in the nucleus of the atom and they make up the major mass of the atom. The electron is located outside of the nucleus and it orbit around the nucleus; it has negligible mass. The electron is negatively charged and because it is located outside of the nucleus, it is the one that is always involved in chemical reactions. There are different types of chemical bonds in chemical compounds and it is electrons that are normally used to form these bonds. During bond formation, electrons can either be donated or shared.

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2 years ago
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Which product forms from the synthesis reaction between lithium (Li) and oxygen (O)?
Advocard [28]

Answer:

A Li2O

Explanation:

Li has a 1+ charge and O has a 2- charge so to balance the charges there needs to be 2 Li for every 1 O

5 0
2 years ago
When 231. mg of a certain molecular compound X are dissolved in 65. g of benzene (CH), the freezing point of the solution is mea
Elan Coil [88]

Answer:

Molar mass X = 18.2 g/mol

Explanation:

Step 1: Data given

Mass of compound X = 231 mg = 0.231 grams

Mass of benzene = 65.0 grams

The freezing point of the solution is measured to be 4.5 °C.

Freezing point of pure benzene = 5.5 °C

The freezing point constant for benzene is 5.12 °C/m

Step 2: Calculate molality

ΔT = i*Kf*m

⇒ΔT = the freezing point depression = 5.5 °C - 4.5 °C = 1.0 °C

⇒i = the Van't hoff factor = 1

⇒Kf = the freezing point depression constant for benzene = 5.12 °C/m

⇒m = the molality = moles X / mass benzene

m = 1.0 / 5.12 °C/m

m = 0.1953 molal

Step 3: Calculate moles X

Moles X = molality * mass benzene

Moles X = 0.1953 molal * 0.065 kg

Moles X = 0.0127 moles

Step 4: Calculate molar mass X

Molar mass X = mass / moles

Molar mass X = 0.231 grams / 0.0127 moles

Molar mass X = 18.2 g/mol

5 0
3 years ago
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