Answer:
8.13 ×10²³ atoms
Explanation:
Given data:
Mass of magnesium = 32.45 g
Number of atoms = ?
Solution:
Number of moles of Mg:
Number of moles = mass/molar mass
Number of moles = 32.45 g/ 24 g/mol
Number of moles = 1.35 mol
Number of atoms:
1 mole contain 6.022×10²³ atoms
1.35 mol × 6.022×10²³ atoms/ 1mol
8.13 ×10²³ atoms
Well you didn’t post any but I’m hoping that either plastic, lead, wood, glass, or paper, are an option.
<span>The answer is D)<em> </em>are compounds that have the same number and types of atoms but are arranged differently.
Source: <em>just took the test :)</em></span>
Answer: 6.162g of Ag2SO4 could be formed
Explanation:
Given;
0.255 moles of AgNO3
0.155 moles of H2SO4
Balanced equation will be given as;
2AgNO3(aq) + H2SO4(aq) -> Ag2SO4(s) + 2HNO3(aq)
Seeing that 2 moles of AgNO3 is required to react with 1 moles of H2SO4 to produce 1 mole of Ag2SO4,
Therefore the number of moles of Ag2SO4 produced is given by,
n(Ag2SO4) = 0.255 mol of AgNO3 ×
[0.155mol H2SO4 ÷ 2 mol AgNO3] x
[ 1 mol Ag2SO4 ÷ 1 mol H2SO4]
= 0.0198 mol of Ag2SO4.
mass = no of moles x molar mass
From literature, molar mass of Ag2SO4 = 311.799g/mol.
Thus,
Mass = 0.0198 x 311.799
= 6.162g
Therefore, 6.162g of Ag2SO4 could be formed
Answer:
345.44 g or 0.34544 kg
Explanation:
Applying
D = m/V...................... Equation 1
Where D = Density of mercury, m = mass of mercury, V = Volume of mercury.
make m the subject of the equation
m = D×V................. Equation 2
From the question,
Given: D = 13.6 g/mL = 13.6 g/cm³, V = 25.4 cm³
Substitute these values into equation 2
m = 13.6×25.4
m = 345.44 g
m = 0.34544 kg
Hence the mass of mercury is 345.44 g or 0.34544 kg
