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Fiesta28 [93]
3 years ago
7

Here is the discharge reaction for an alkaline battery: zn(s) + 2mno2(s) + h2o(l)\longrightarrow⟶⟶zn(oh)2(s) + mn2o3(s) which sp

ecies is reduced as the battery is discharged?
Chemistry
2 answers:
ollegr [7]3 years ago
8 0
The reaction is 
Zn(s) + 2MnO₂(s) + H₂O(l) ⟶ Zn(OH)₂(s) + Mn₂O₃(s)

The reactants are Zn(s) and MnO₂(s) while Zn(OH)₂(s) and Mn₂O₃(s) products.

Let's see the oxidation state of each compound.
sum of the o.s. of the each element of compound = charge of the compound

O.s of O = -2
O.s of OH⁻ = -1

O.s of Zn(s) = 0

O.s of Mn in MnO₂(s) = x
         x + (-2) * 2 = 0
             x            = +4


O.s of Zn in Zn(OH)₂(s) = a
          a + (-1) * 2 = 0
                 a         = +2

O.s of Mn in Mn₂O₃(s) = b
          2*b + (-2) * 3 = b
                         2b   = 6
                           b   = +3
Since the O.s is reduced in Mn from +4 to +3, the reduced species is Mn₂O₃(s).

sesenic [268]3 years ago
5 0

Answer:

Explanation:

the reaction is  

Zn(s) + 2MnO₂(s) + H₂O(l) ⟶ Zn(OH)₂(s) + Mn₂O₃(s)

This is the discharge reaction, where Zn is undergoing oxidation and Mn is undergoing reduction.

The anode reaction is:

Zn(s)+2OH^{-}(aq) ---> ZnO(s) + H_{2} O(l) + 2e

The cathode reaction is:

MnO_{2}(s)+H_{2}O(l)+2e--->Mn_{2}O_{3} }+2OH^{-}(aq)

Thus here MnO₂  is undergoing reduction (and the element undergoing reduction is Mn).

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Are these gases lighter than or denser than air? How can you tell?
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Some Gases are lighter than air
Remember,Air is a mixture of gases
So you cant tell!
It depends on the gas
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3 0
3 years ago
Refer to the Chemical Compounds table above. How many total elements are in<br> Ethanol?
Korolek [52]

Answer:

3 element i.e carbon (C), hydrogen (H) and oxygen.

Explanation:

The following data were obtained from the question:

Subtance >>>>>>>> Chemical Formula

Glucose >>>>>>>>> C₆H₁₂O₆

Methane >>>>>>>> CH₄

Ethanol >>>>>>>>> C₂H₅OH

Hydrogen peroxide >> H₂O₂

From the above table, we can see that ethanol (C₂H₅OH) contains carbon (C), hydrogen (H) and oxygen

Therefore, the total number of elements present in ethanol, C₂H₅OH is 3.

8 0
3 years ago
A 0.500-g sample of KCl is added to 50.0g of water in a calprimeter (Figure 5.12) If the temperature decreases by 1.05C. what is
Sauron [17]

Answer : The reaction is endothermic.

Explanation :

Formula used :

Q=m\times c\times \Delta T

where,

\Delta T = change in temperature = 1.05^oC

Q = heat involved in the dissolution of KCl = ?

m = mass = 0.500 + 50.0 = 50.5 g

c = specific heat of resulting solution = 4.18J/g^oC

Now put all the given value in the above formula, we get:

Q=50.5g\times 4.18J/g^oC\times 1.05^oC

Q=+221.64J

The heat involved in the dissolution of KCl is positive that means as the change in temperature decreases then the reaction is endothermic and as the change in temperature increases then the reaction is exothermic.

Hence, the reaction is endothermic.

8 0
3 years ago
You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of a
balandron [24]

Answer:

56.9 mmoles of acetate are required in this buffer

Explanation:

To solve this, we can think in the Henderson Hasselbach equation:

pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])

To make the buffer we know:

CH₃COOH  +  H₂O  ⇄   CH₃COO⁻  +  H₃O⁺     Ka

We know that Ka from acetic acid is: 1.8×10⁻⁵

pKa = - log Ka

pKa = 4.74

We replace data:

5.5 = 4.74 + log ([acetate] / 10 mmol)

5.5 - 4.74 = log ([acetate] / 10 mmol)

0.755 = log ([acetate] / 10 mmol)

10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)

5.69 = ([acetate] / 10 mmol)

5.69 . 10 = [acetate] → 56.9 mmoles

6 0
3 years ago
Think of a bath sponge. What happens when you squeeze it? How could you explain it from the point of view of the state of the ag
harkovskaia [24]

Answer:

What happens when it is squeezed is that its volume increases, the pressure of the material increases.

Explanation:

This is due to the fact that the elastic modulus of the sponge is high and withstands broad forces without deforming its structure, since the force is made within the proportional limit of its particles without modifying or permanently deforming them, that is why when stopping doing pressure or force on it its shape returns to being the original, this also happens due to the phenomenon of resilience

3 0
3 years ago
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