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3 years ago

What is the slope of the line shown below? (6,6) and (1,-4)

Mathematics

1 answer:

Nady [450]3 years ago

4 0

Answer:

2(C)

Step-by-step explanation:

You can use the slope formula to answer this which is y₁ - y₂ divided by x₁ - x₂. Let's say that (x₁, y₁) is (6,6) and the (x₂, y₂) is (1, -4). We can then substitute these values into the formula.

This would become 6- (-4) divided by 6-1.

This can be further simplified as shown:

=6+4 divided by 5

=10/5

Therefore, 2 is the slope of the line

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The comprehensive strength of concrete is normally distributed with μ = 2500 psi and σ = 50 psi. Find the probability that a ran

VARVARA [1.3K]

Answer:

The probability that the diameter falls in the interval from 2499 psi to 2510 psi is 0.00798.

Step-by-step explanation:

Let's define the random variable, $X =$ "Comprehensive strength of concrete". We have information that $X$ is normally distributed with a mean of 2500 psi and a standard deviation of 50 psi (or a variance of 2500 psi). In other words, $X \sim N(2500, 2500)$ .

We want to know the probability of the mean of X or $\bar{X}$ that falls in the interval $[2499;2510]$ . From inference theory we know that :

$\bar{X} \sim N(2500, \frac{2500}{5}) \Rightarrow \bar{X} \sim N(2500,500)$

Now we can find the probability as follows:

$P(2499 \leq \bar{X} \leq 2510) \Rightarrow P(\frac{2499 - 2500}{500} \leq \frac{\bar{X} - 2500}{500} \leq \frac{2499 - 2500}{500} ) \Rightarrow\\\Rightarrow P(-0.002 \leq \frac{\bar{X} - 2500}{500} \leq 0.02 ) \Rightarrow P(-0.002 \leq Z \leq 0.02 )$

Where $Z \sim N(0,1)$ , then:

$P(-0.002 \leq Z \leq 0.02 ) \approx P(0 \leq Z \leq 0.02 ) = P(Z \leq 0.02 ) - P(Z \leq 0) \\P(0 \leq Z \leq 0.02 ) = 0.50798 - 0.5 = 0.00798$

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3 years ago

suppose that an 1994 finline produce 18.036 million lb of weed. The total World production that your total to 137 million lb of

Degger [83]

One may note the country's name is not finline or Finley, is Finland.

so, in short, if we take 137 to be the 100%, how much is 18.036 in percentage off of it?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
137&100\\
18.036&x
\end{array}\implies \cfrac{137}{18.036}=\cfrac{100}{x}\implies x=\cfrac{18.036\cdot 100}{137}$

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2 years ago