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Stella [2.4K]
3 years ago
5

Thin Layer Chromatography consists of three parts: The analyte, the stationary phase, and mobile phase. Match each of these term

s to what it was in our experiment. Stationary Phase ____ a) The solvent
Mobile Phase ____ b) Silica

Analyte ____ c) One of the analgesiscs
Physics
1 answer:
Margaret [11]3 years ago
8 0

Answer:

Analyte⇒ one of analgesics

stationery phase⇒ silica

mobile phase⇒ solvent

Explanation:

during the thin layer chromatography non volatile mixtures are separated.The technique is performed on the plastic or aluminum foil that is coated with a thin layer.

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If the jet is moving at a speed of 1140 km/h at the lowest point of the loop, determine the minimum radius of the circle so that
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To solve this problem we will apply the concepts related to the centripetal Force and the Force given by weight and formulated in Newton's second law. Through the two expressions we can find the radius of curve made in the hand. To calculate the normal force, we will include the concepts of sum of forces to obtain the net force on the body at the top and bottom of the maneuver. The expression for centripetal force acting on the jet is

F_c = \frac{mv^2}{r}

According to Newton's second law, the net force acting on the jet is

F = ma

Here,

m = mass

a = acceleration

v = Velocity

r = Radius

PART A ) Equating the above two expression the equation for radius is

\frac{mv^2}{r} = ma

r = \frac{v^2}{a}

Replacing with our values we have that

r = \frac{(1140km/hr[\frac{1000m}{1km}\frac{1hour}{3600s}])^2}{7(9.8m/s^2)}

r = 1.462*10^3m

PART B )

<u>- The expression for effective weight of the pilot at the bottom of the circle is</u>

N = mg +\frac{mv^2}{r}

N = (69kg)(9.8m/s^2)+\frac{(69)(1140km/hr[\frac{1000m}{1km}\frac{1hour}{3600s}])^2}{1.462*10^3m}

N = 5408.87N

<em>Note that the normal reaction N is directed upwards and gravitational force mg is directed downwards. At the bottom of the circle, the centripetal force is directed upwards. So the centripetal force is obtained from the gravitational force and the normal reaction. </em>

<u>- The expression for effective weight of the pilot at the top of the circle is</u>

N = mg -\frac{mv^2}{r}

N = (69kg)(9.8m/s^2)-\frac{(69)(1140km/hr[\frac{1000m}{1km}\frac{1hour}{3600s}])^2}{1.462*10^3m}

N = 4056.47N

<em>Note that at the top of the circle the centripetal force is directed downwards. So the centripetal force is obtained from normal reaction and the gravitational force. </em>

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Answer:

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Its diamond i am 100% right!

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A man takes 20 seconds to climb 5m up a ladder. He weighs 720N. Calculate the power he must deliver to do this.
Inessa05 [86]

Answer:

180 W

Explanation:

The work done by the man against gravity is equal to its gain in gravitational potential energy:

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Substituting,

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The power he must deliver is given by

P=\frac{W}{t}

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Substituting,

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