A circular loop of wire is positioned so the normal to its area points vertically upward. A bar magnet is dropped from above the
1 answer:
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Answer:
0.92 μC
Explanation:
In a parallel-plate capacitor, the electric field formed is equal to the charge density divited by the vacuum permisivity e0, as there are no dielectric between the plates. e0 is equal to 8.85*10^-12 C^2/Nm^2. The charge density is the total charge of each individual plate divided by its area. Then, the maximum charge allowed will be equal to:
or 0.92 μC
Answer:
1/18
Explanation:
The number of ways in which two die can be thrown is the sample space of the experiment
(1,1), (1,2) (1,3), (1,4) (1,5) (1,6)
(2,1), (2,2) (2,3), (2,4) (2,5) (2,6)
(3,1), (3,2) (3,3), (3,4) (3,5) (3,6)
(4,1), (4,2) (4,3), (4,4) (4,5) (4,6)
(5,1), (5,2) (5,3), (5,4) (5,5) (5,6)
(6,1), (6,2) (6,3), (6,4) (6,5) (6,6)
From here it can be seen that there are only two cases where the sum on the two die is 11 i.e., (6,5) and (5,6)
∴ Probability of getting 11 is<u> 1/18</u>
Explanation:
Let x = distance of from the fulcrum and let's assume that the counterclockwise direction is positive. In order to attain equilibrium, the net torque
about the fulcrum is zero:
Solving for <em>x</em>,