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Sergio039 [100]
4 years ago
6

Calculate the temperature of gas that originally occupied 3.45L and is expanded to 5.25L. The original temperature of the gas wa

s 282K and the pressure remains constant.
Chemistry
1 answer:
Marat540 [252]4 years ago
6 0
V1/V2=T1/T2
\frac{V1}{ \:V2} =  \frac{T1}{T2} \\  \frac{3.45}{5.25} =  \frac{282}{T2}  \\ T2 =  \frac{5.25 \times 282}{3.45}  \\ T2 = 429 \: k
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