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Mademuasel [1]
3 years ago
11

Please help b4 i literally will get killedd PLZZZ.

Chemistry
1 answer:
Nutka1998 [239]3 years ago
5 0
This is the answer
1st choice

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An atom has 24 protons and 23 electrons and 28 neutrons what charge does this atom have?
alina1380 [7]

Answer:

1+

Explanation:

the number of protons tells you which element it is in the periodic table, you can notice that there is 1 less electron that then there is protons which means that the element had to give 1 electron away. When you get rid of 1 e- you have 1 proton more that electrons so that's why it's 1+

also the element is Cr

3 0
3 years ago
The hcl(g) molecule has a bond length of 127 pm and a dipole moment of 1.08
Roman55 [17]

Let us assume that this molecule is 100 percent ionic. In that case, the charges are distinguished by a bond length.

h = Q × r

= (160 × 10⁻¹⁹ c) (127 × 10⁻¹² m) (10 / 3.336 × 10⁻³⁰ cm)

= 6.09 D.

The actual dipole moment is = 1.08 D

Therefore, the percent ionic character is,

= 1.08 D / 6.09 D × 100

= 17.7 %.

6 0
3 years ago
How many moles of nh3 can he produced from the reaction of 38 g of n2
fiasKO [112]
N₂ + 3 H₂ → 2 NH₃

number of moles of N₂ = 38 g / 28 g/mol = 1.357 mol

1 mole of N₂ gives 2 moles of NH₃
1.357 mol of N₂ will give ?? mole NH₃

= 2 x 1.357 = 2.7 mol NH₃
5 0
4 years ago
What is the relationship between the electronic configuration, group and period numbers?
Margaret [11]

Answer: the number of circles in the electronic configuration of an element is represented in the periodic table as the period number that element is situated in. the number of electrons in the outermost shell of an element is represented in the periodic table as the group number that element is situated in.

Explanation: hope it helps :)

6 0
3 years ago
It was calculated that 4.3mL of 0.417 M HCl is required to titrate 11.9 mL of 0.151 M Mg(OH)2. Show evidence 2 HCl(aq) + Mg(OH)2
Lapatulllka [165]

Answer:

See explanation.

Explanation:

Hello,

In this case, for the described chemical reaction:

2 HCl(aq) + Mg(OH)2(aq) → MgCl2(aq) + 2 H2O(l)

We can notice there is a 2:1 molar ratio between the moles of hydrochloric acid and magnesium hydroxide, therefore, at the equivalence point:

n_{HCl}=2*n_{Mg(OH)_2}

And in terms of volumes and concentrations we verify:

V_{HCl}M_{HCl}=2*V_{Mg(OH)_2}M_{Mg(OH)_2}

So we use the given data to proof it:

4.3mL*0.417M=2*11.9mL*0.151M\\1.793=3.594

Therefore, we can conclude the data is wrong by means of the 2:1 mole ratio that for sure was not taken into account. This is also supported by the fact that normalities are actually the same, but the nomality of magnesium hydroxide is the half of the hydrochloric acid normality since the acid is monoprotic and the base has two hydroxyl ions.

Best regards.

4 0
3 years ago
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