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Mademuasel [1]
3 years ago
11

Please help b4 i literally will get killedd PLZZZ.

Chemistry
1 answer:
Nutka1998 [239]3 years ago
5 0
This is the answer
1st choice

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How many moles of ammonia are in 735. mL of a 4.25 M aqueous ammonia solution?
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Answer:

*moles = molarity(M=moles/L) * volume (L)

so, you have 4.25 * 0.735 moles

*NH3

* M=n/v

*To determine the number of significant figures in a number use the following 3 rules: Non-zero digits are always significant. Any zeros between two significant digits are significant. A final zero or trailing zeros in the decimal portion ONLY are significant.

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Two soccer teams, the Bears and the Panthers, played games at the same time in two different locations. The Bears game was playe
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Explanation:

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3 years ago
During which process are of rock material being moved over earth’s surface by water and wind?
shtirl [24]
Wind and water erosion
 
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Identify special properties of water including surface tension and specific heat
anyanavicka [17]
Specific Heat-the heat required to raise the temperature of the mass of a substance by a cetain amount
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6 0
3 years ago
How many grams of CuSO4 • 5H2O do you need to make 0.8 L of a 0.6 M solution
Bumek [7]
<h3><u>Unders</u><u>tanding</u><u> </u><u>the</u><u> </u><u>conc</u><u>ept</u><u>:</u><u>-</u></h3>

Here the concept of Molarity used .We will put the formula of Molarity then we find moles of copper sulphate .Then we can find the.Given weight of Copper sulphate.So let's do

<h3>Solution:-</h3>

  • Volume of Solvent=0.8L
  • Molarity=0.6M

We know

\boxed{\sf Molarity=\dfrac{Moles\:of\: solute}{Volume\:of\: Solvent \:in\;L}}

\\ \rm\longmapsto Moles\:of\: solute=Molarity\times Volume\:of\: Solvent\:in\:L

\\ \rm\longmapsto Moles\:of\: Solute=0.8(0.6)

\\ \rm\longmapsto Moles\:of\: Solute=0.48mol

Now

Molar Mass of Solute:-

\\ \rm\longmapsto CuSO_4.5H_2O

\\ \rm\longmapsto 65u+32u+4(16u)+5(2\times 1u+16u)

\\ \rm\longmapsto 96u+64u+5(2+16)

\\ \rm\longmapsto 160u+90u

\\ \rm\longmapsto 250u

\\ \rm\longmapsto 250g/mol

Now

\boxed{\sf No\:of\:moles=\dfrac{Given\:Mass}{Molar\:Mass}}

\\ \rm\longmapsto Given\:Mass=No\:of\:Moles\times Molar\:Mass

\\ \rm\longmapsto Given\:Mass=250(0.48)

\\ \rm\longmapsto Given\:Mass=120g

8 0
3 years ago
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