The term is alkenes. one double carbon-carbon bond is referred to as Alkenes or Alkynes
Answer:
P₂ = 3.61 atm
Explanation:
Given data:
Initial pressure of tank = 3.20 atm
Initial temperature = 22.0°C
Final temperature = 60.0°C
Final pressure = ?
Solution:
Initial temperature = 22.0°C (22.0 +273 = 295 K)
Final temperature = 60.0°C (60 +273 = 333)
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
3.20 atm / 295 K = P₂/333 K
P₂ = 3.20 atm × 333 K / 295 K
P₂ = 1065.6 atm. K /295 K
P₂ = 3.61 atm
Answer:
Explanation:
You calculate the energy required to break all the bonds in the reactants.
Then you subtract the energy needed to break all the bonds in the products.
CH₃CH₂OH + 3O₂ ⟶ 2CO₂ + 3H₂O
Bonds: 5C-H 1C-C 1C-O 1O-H 3O=O 4C=O 6O-H
D/kJ·mol⁻¹: 413 347 358 467 495 799 467
