Question

If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its resulting speed?

Answer 1

Answer:

Speed of the electron will be $v=5.896\times 10^7m/sec$

Explanation:

We have given that charge on electron $e=1.6\times 10^{-19}C$

Mass of electron $m=9.11\times 10^{-31}kg$

Potential difference = $V=9.9KV=9.9\times 10^3volt$

Now according to energy conservation $eV=\frac{1}{2}mv^2$

$1.6\times 10^{-19}\times 9.9\times 10^3=\frac{1}{2}\times 9.11\times 10^{-31}v^2$

$v=5.896\times 10^7m/sec$