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Anna [14]
2 years ago
14

Write the standard form of the line that contains a slope -3/8 and passes through the point (5, -4).

Mathematics
1 answer:
Kipish [7]2 years ago
7 0

Answer:

y+3/8x=-17/8

Step-by-step explanation:

y=mx+b

y=-3/8x+b

-4=-3/8(5)+b

-4=-15/8+b

-32/8+15/8=b

-17/8=b

y=-3/8x-17/8

change to standard form where x and y are on one side of the equation

y+3/8x=-17/8

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CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION
Murljashka [212]

Answer:

The value of DC is 66.34.

Step-by-step explanation:

The triangles ABC and DCA are right angled triangles.

The straight line AC is a bisector for angles C and A.

The measure of ∠C is 30°.

Then the measure of angles BCA and ACD will be 15° each.

The measure of angle DAB is 150°.

Then the measure of angles DAC and BAC will be 75° each.

Now consider the right angled triangle ABC.

The measure of side AC is:

AC^{2}=AB^{2}+BC^{2}\\AC=\sqrt{AB^{2}+BC^{2}}\\=\sqrt{4^{2}+(10\sqrt{3})^{2}}\\=\sqrt{316}

Consider the right angled triangle DCA.

The angle DAC measure 75°.

Using the trigonometric identities compute the value of Perpendicular DC as follows:

tan\ 75^{o}=\frac{DC}{\sqrt{316}}\\\\DC=3.732\times\sqrt{316}\\\\DC=66.34

Thus, the value of DC is 66.34.

7 0
3 years ago
Can anyone help with this problem?
Pie

Answer:

The numerator factors to

(x + 2)(x - 1)

The denomenator factors to

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