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Marysya12 [62]
3 years ago
6

Which is a factor on determining the average atomic mass of an element

Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
8 0

Answer:

Relative abundance of each isotopes of an element.

Explanation:

Consider the following example:

Uranium is used in nuclear reactors and is a rare element on earth. Uranium has three common isotopes. If the abundance of 234U is 0.01% the abundance of 235U is 0.71% and the abundance of 238U is 99.28% what is the average atomic mass of uranium

Abundance of U²³⁴ = 0.01%

Abundance of U²³⁵ = 0.17%

Abundance of U²³⁸ = 99.28%

Average atomic mass = ?

Solution:

Average atomic mass of uranium = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) +(abundance of 3rd isotope × its atomic mass) / 100

Average atomic mass of uranium= (234×0.01)+(235×0.71)+(238×99.28)/100

Average atomic mass of uranium=  2.34 + 166.85 + 23628.64 / 100

Average atomic mass of uranium= 23797.83 / 100

Average atomic mass of uranium= 237.98 amu.

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3 years ago
The escape of molecules from the surface area of a liquid is known as
Tasya [4]

Answer:

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8 0
4 years ago
How do you calculate a wavelength of light emitted when
Novosadov [1.4K]

Answer: Wavelength of light emitted when  the electron in doubly ionized lithium makes a transition  from E12 to E8 is  0.1050\times 10^{-4m

Explanation:

Li:3:1s^22s^1

Li^{2+}:1:1s^1

Using Rydberg's Equation for hydrogen and hydrogen like atom:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant

n_f = Higher energy level  

n_i= Lower energy level

We have:

n_f=8, n_i=12

R_H=1.097\times 10^7 m^{-1}

\frac{1}{\lambda}=1.097\times 10^7 m^{-1}\times \left(\frac{1}{12^2}-\frac{1}{8^2} \right )

\frac{1}{\lambda}=1.097\times 10^7 m^{-1}\times \frac{5}{576}

\frac{1}{\lambda}=9.523\times 10^4 m

\frac{1}{\lambda}=9.523\times 10^4 m

{\lambda}=0.1050\times 10^{-4}m

The wavelength of the photon emitted when the hydrogen atom undergoes a transition is 0.1050\times 10^{-4m

8 0
3 years ago
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